在Unity中不活动后如何使光标消失 [英] How to make cursor dissapear after inactivity in Unity
问题描述
我的目标很简单,就像许多应用程序一样,我希望在用户闲置一段时间后使我的光标不可见.
My goal is simple, like a lot of applications, I want to make my cursor invisible after a certain time of inactivity of my user.
我的解决方案似乎没有真正地优化,这是算法:
My solution doesn't seem really optimized, here's the algorithm :
void Start {
Timer t = new Timer(5000);//Create a timer of 5 second
t.start();
}
void Update {
if(MouseMoved){
t.reset();
}
timeLeft = t.deltaTime;
if ( timeLeft == 5000 )
{
Cursor.visible = false;
}
}
我真的不希望在每一帧都检查,如果我的鼠标移动了,我宁愿我的鼠标移动会触发一些东西,但是我迷路了,有人能更好吗?解决方案?
I really don't like to check at every frame if the mouse is moved, I'd prefer that my mouse moved trigger something, but I'm lost here, is anyone have a better solution ?
推荐答案
我知道有两种方法可以在更新循环之外检查这种情况:
There are two ways to check for things like this outside of the update loop, that I know of:
1-自定义事件.
编写自己的自定义事件将使您可以在更新函数之外调用"OnMouseMove()"之类的内容,并且仅在鼠标光标的位置更改时才执行.
Writing your own custom event would allow you to call something like "OnMouseMove()" outside of the update function and it would only execute when the mouse cursor's position changes.
2-协程
创建一个单独的协程将使您执行此检查的频率降低.为此,您需要制作一个IEnumerator并将鼠标移动逻辑放在其中.像这样:
Creating a separate coroutine would allow you to perform this check less frequently. To do this, you make an IEnumerator and put your mouse movement logic in there. Something like:
IEnumerator MouseMovement()
{
while(true)
{
if(MouseMoved)
{
//Do stuff
}
yield return new WaitForSeconds(1f);
}
}
该协程在运行时每秒执行一次检查.您将通过说出协程开始:
That coroutine would perform the check once every second while it is running. You would start the coroutine by saying:
StartCoroutine(MouseMovement());
要阻止它,请致电
StopCoroutine(MouseMovement());
如果您在计时器到0时启动它,并在光标移动时停止它,则还可以防止协程程序始终运行,仅在光标处于非活动状态时使用它.
If you Start it when the timer reaches 0 and stop it when the cursor is moved, you can also prevent the coroutine from running all the time, only using it while the cursor is inactive.
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