如何在OnCollisionEnter2D()中找到冲突的游戏对象的索引 [英] How to find index of colliding Game Object in OnCollisionEnter2D()

问题描述

我已经创建了一个预制件，并在一个脚本中实例化了它多次，并将其附加到另一个游戏对象上，如下所示.

I have created a prefab and instantiated it a number of times in a script that it attached to another game object as below.

void Start () {

    badGuys= new List<GameObject> ();

    int numberOfBadGuys = 6;
    Camera camera = GameObject.FindGameObjectWithTag ("MainCamera").GetComponent<Camera> ();

    for (int i = 1; i < numberOfBadGuys + 1; i++) {
        GameObject badGuyObject =  (GameObject)Instantiate(badGuy, new Vector3(Screen.width*i/2, Screen.height*i/6, camera.nearClipPlane ), Quaternion.identity );
        badGuys.Add(badGuyObject);
    }

}

由于数组中所有实例化的对象都具有相同的标签和游戏对象，如何找到数组中碰撞对象的索引?

Since all of the instantiated objects in the array have the same tag and game object, how can I find the index of the colliding object in the array?

void OnCollisionEnter2D(Collision2D col)    {
    Debug.Log("collision has began");

    if (col.gameObject.tag == "badGuy") {
             // how can I tell the index of colliding game object in badGuys array
      }
}

推荐答案

您应该能够像这样循环并比较GameObject:

You should be able to just loop and compare the GameObject like this:

void OnCollisionEnter2D(Collision2D col)
{
    Debug.Log("collision has began");

    int collidedBadGuyIndex = -1; //This variable should be outside this function.

    if (col.gameObject.tag == "badGuy")
    {
        for (int i=0; i<badGuys.Length; i++)
        {
            if (col.gameObject.Equals(badGuys[i]))
            {
                collidedBadGuyIndex = i;
                break;
            }
        }
    }
}

如果这不起作用，则可以将脚本添加到badguys中(例如BadGuyScript.cs)，并在脚本内部添加一个名为bool hasCollided = false;的变量，然后当badguy碰撞时将变量设置为true循环所有badguys，并找到值等于true的badguy的索引.

If this doesn't work then you could add a script to the badguys (i.e. BadGuyScript.cs) and inside of the script add a variable called bool hasCollided = false; then when the badguy collides set the variable to true and then loop all the badguys and find the index of the badguy that has the value equal to true.

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