当我使用var_dump变量调试php时，总是在开始时输出文件路径吗? [英] When I debug php with var_dump variable it always outputs file path at the beginning?

问题描述

我将Ubuntu 7与PHP 7配合使用.

I am using Ubuntu with PHP 7.

PHP 7.0.5-3+donate.sury.org~xenial+1 (cli) ( NTS )
Copyright (c) 1997-2016 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2016 Zend Technologies
    with Zend OPcache v7.0.6-dev, Copyright (c) 1999-2016, by Zend Technologies
    with Xdebug v2.4.0, Copyright (c) 2002-2016, by Derick Rethans

当我使用var_dump显示一些变量来调试PHP脚本时:

When I debug a PHP script by using var_dump to show some variable:

<?php
var_dump('tmp string');
var_dump(true);

以下是其输出:

/var/www/example.com/test.php:3:string 'tmp string' (length=10)
/var/www/example.com/test.php:4:boolean true

为什么总是与以前的文件路径一起输出?

Why does it always output with the file path before?

我希望它输出如下:

string 'tmp string' (length=10)
boolean true

推荐答案

您看到的输出来自Xdebug扩展. (不带扩展名的var_dump输出纯文本，未格式化的文本.)

The output you're seeing is from the Xdebug extension. (Without the extension, var_dump outputs plain, unformatted text.)

从Xdebug 2.3开始，设置xdebug.overload_var_dump具有新的默认值2，该默认值会将文件名和行号添加到对var_dump的任何调用的输出中.有关更多信息，请参见文档.我同意这没什么用，特别是对于简单的输出(例如短字符串/数字).

From Xdebug 2.3, the setting xdebug.overload_var_dump has a new default value of 2 which adds the filename and line number to the output from any call to var_dump. See the docs for more info. I agree it's not that useful, especially for simple output like short strings/numbers.

要删除文件名，您可以在php.ini文件中将选项设置为旧值1:

To remove the filename you can set the option to the old value of 1 in your php.ini file:

[xdebug]
xdebug.overload_var_dump = 1

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