使用正则表达式从数字范围中排除某些数字 [英] Exclude certain numbers from range of numbers using Regular expression

问题描述

有人可以帮助我使用正则表达式吗?在正则表达式中，我们可以从一系列数字中排除某些介于中间的数字.

Could some one help me with the regular expression, where we can exclude certain numbers in between from a range of numbers.

当前，^([1-9][0][0-9])$是已配置的正则表达式.现在，如果我想从中排除一些数字/一个数字(501，504)，那么正则表达式的外观如何.

Presently, ^([1-9][0][0-9])$ is the regular expression that is configured. Now if i want to exclude a few numbers/one number(501,504) from it, then how would the regular expression look/be.

推荐答案

在此答案中更详细地描述，您可以将以下正则表达式与负向超前"命令?!一起使用:

Described in more detail in this answer, you can use the following regex with the "Negative Lookahead" command ?!:

^((?!501|504)[0-9]*)$

您可以看到正在执行的正则表达式&此处说明: https://regex101.com/r/mL0eG4/1

You can see the regex being executed & explained here: https://regex101.com/r/mL0eG4/1

/^((?! 501 | 504)[ 0-9 ] *)$/mg

• ^在行的开头断言位置
• 第一个捕获组((?！501 | 504)[0-9] *)
  • (?! 501 | 504)负前瞻-断言不可能匹配下面的正则表达式
    • 第一种选择:501
      • 501从字面上匹配字符501

/^((?!501|504)[0-9]*)$/mg

• ^ assert position at start of a line
• 1st Capturing group ((?!501|504)[0-9]*)
  • (?!501|504) Negative Lookahead - Assert that it is impossible to match the regex below
    • 1st Alternative: 501
      • 501 matches the characters 501 literally

• 504从字面上匹配字符504

• 量词:*零次至无限次，尽可能多地返回[greedy]
• 0-9所需的单个字符，范围在0到9之间

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