在R中使用Weibull的累积分布函数 [英] Use the cumulative distribution function of Weibull in R

问题描述

我必须模拟系统的故障时间，为此，我必须使用Weibull分布，其危险率降低"且形状为"0.7-0.8".我必须为该函数生成一个包含100个结果的文件，该函数使用从0到1的随机数.

I have to simulate a system's fail times, to do so I have to use the Weibull distribution with a "decreasing hazard rate" and a shape of "0.7-0.8". I have to generate a file with 100 results for the function that uses random numbers from 0 to 1.

所以我一直在搜索，发现了这个R函数:

So I've been searching a bit and I found this R function:

    pweibull(q, shape, scale = 1, lower.tail = T, log.p = F)

还有其他一些(rweibull，qweibull ...)，但是我认为这是我必须使用的，因为如锻炼说明所述，这是累积分布之一.问题是我不熟悉R，并且我真的不知道必须向该函数传递哪些参数.

There are some other (rweibull,qweibull...) but I think this is the one that I have to use, since is the cumulative distribution one, as the exercise statement says. The problem is that I am new to R and that I don't really know what parameters I have to pass to this function.

我猜形状应该为0.7-0.8，比例为1.对于q参数，我是否应该创建一个100个数字的随机矢量，其值是0到1?如果是这样，该如何做?还有关于如何将结果数据导出到文件的提示吗?

I'm guessing shape should be 0.7-0.8, and scale 1. For q parameter, should I create a random vector of 100 numbers with 0 to 1 values? If so, any tip of how to do it? Also any tip on how to export the resultant data to a file?

推荐答案

我不确定问题是什么，但是如果您想从Weibull分布中生成100个形状参数为0.75的值，请使用rweibull(100, 0.75).

I'm not sure what the question is, but if you want to generate 100 values drawn from Weibull distribution with shape parameter of 0.75 use rweibull(100, 0.75).

如果要查看它们大于零的可能性，请使用pweibull(rweibull(100, 0.75), 0.75).

If you want to see what the probability is that they are larger than zero, use pweibull(rweibull(100, 0.75), 0.75).

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You should also be aware that there is a general no-homework rule on these sites.

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