xml_grep从元素获取属性 [英] xml_grep get attribute from element

问题描述

使用xml_grep是否有可能(如果是，如何)从特定元素获取特定属性的值?我似乎只能在标签之间输出信息.

Is it possible (and if so, how) with xml_grep to get the value of a specific attribute from a specific element? I only seem to be able to output the information between tags.

示例:

    <eid>
       <identity nationalnumber="13021912354" dateofbirth="20130219" gender="male">
          <name>Menten</name>
          <firstname>Kasper</firstname>
          <middlenames>Marie J</middlenames>
          <nationality>Belg</nationality>
          <placeofbirth>Sint-Truiden</placeofbirth>
          <photo>base64-string</photo>
       </identity>
    </eid>

从"identity"元素中输出"nationalnumber"属性的值(在本例中为13021912354)

output the value (in this case: 13021912354) of the 'nationalnumber'-attribute from the 'identity'-element

推荐答案

使用xmllint:

xmllint --xpath 'string(//identity/@nationalnumber)' file.xml

对于debian发行版(或衍生版本)，xmllint是 libxml2-utils 软件包的一部分并可以这样安装:

For debian distro (or derivatives) xmllint is part of the libxml2-utils package and can be installed so:

apt-get install libxml2-utils

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