Zend Honeypot验证 [英] Zend Honeypot Validation

问题描述

在我的引导程序上，我没有一个类，它是一个简单的php文件:

On my bootstrap I don't have a class, it's a simple php file:

我在此处添加了

$loader = Zend_Loader_Autoloader::getInstance ();
$loader->setFallbackAutoloader ( true );
$loader->suppressNotFoundWarnings ( false );

//resource Loader
$resourceLoader = new Zend_Loader_Autoloader_Resource(array(
                'basePath' => APPLICATION_PATH,
                'namespace' => '',
            ));

$resourceLoader->addResourceType('validate', 'validators/', 'My_Validate_');

$loader->pushAutoloader($resourceLoader);

然后，在应用程序/验证器中，我拥有:

Then, in application/validators I have:

class My_Validate_Spam extends Zend_Validate_Abstract {

    const SPAM = 'spam';  

    protected $_messageTemplates = array(  
        self::SPAM => "Spammer"  
    );  

    public function isValid($value, $context=null)  
    {  

        $value = (string)$value;  
        $this->_setValue($value);  

        if(is_string($value) and $value == ''){  
            return true;  
        }  

        $this->_error(self::SPAM);  
        return false;  

    }  
}

在我的表单构造函数中，我有:

In my form constructor I have:

$this->addElement(  
                'text',  
                'honeypot',  
                array(  
                    'label' => 'Honeypot',  
                    'required' => false,  
                    'class' => 'honeypot',  
                    'decorators' => array('ViewHelper'),  
                    'validators' => array(  
                        array(  
                            'validator' => 'Spam'  
                        )  
                    )  
                )  
            );  

最后我认为:

<dt><label for="honeypot">Honeypot Test:</label></dt>
<dd><?php echo $this->form->honeypot;?></dd>

尽管如此，我还是通过填充或不填充该文本字段来接收表单数据. 我在这里想念什么?

Despite all this, I receive my form data, either by filling or not filling that text field. What am I missing here ?

非常感谢.

推荐答案

那是预期的行为. $ honeypot是一个表单元素.现在，假设您有一个表单$ hp_form，其中$ honeypot是分配的元素之一.

Thats expected behaviour. $honeypot is a form-element. Now, let's say you have a form $hp_form where $honeypot is one of the elements assigned.

现在，在您的控制器中只需使用类似以下内容的

Now, in your controller simply use something like:

 if ($hp_form->isValid($this->getRequest()->getPost())) {
     // do something meaningful with your data here
 } 

也许您还想检查一下，是否是第一次显示该表单，或者用户是否已提交该表单:

Probably you also want to check, if you display the form for the first time or if the user submitted the form:

 if ($this->getRequest()->isPost() && 
        false !== $this->getRequest()->getPost('submit_button', false)) {
     if ($hp_form->isValid($this->getRequest()->getPost())) {
         // do something meaningful with your data here
     } 
}

...假设您的提交按钮的ID为"submit_button".

...assuming that your submit button has the id 'submit_button'.

希望这会有所帮助

再见， 基督徒

Bye, Christian

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