使用Scala argonaut编码嵌套类 [英] Encoding nested classes using scala argonaut

问题描述

我正在尝试对案例类进行编码/解码

I'm trying to encode/decode following case class

case class Person(name: String, age: Int, childs: List[Person])

使用以下代码:

object Person {
    implicit def PersonCodecJson =
        casecodec3(Person.apply, Person.unapply)("name", "age", "childs")

}

使用argonaut，但出现以下编译器错误:

with argonaut, but I'm getting the following compiler error:

could not find implicit value for evidence parameter of type argonaut.EncodeJson[List[Person]]

很显然，编译器不知道如何处理List [Person]的编码，因为它在定义如何编码Person的内部使用.

Obviously, the compiler doesn't know how to handle encoding of List[Person], because it's used inside the definition of how to encode Person.

是否有一种聪明的方法告诉argonaut如何正确编码?

Is there a clever way to tell argonaut how to encode it the right way?

更新:感谢Travis:现在正在编译，但是无法正常工作.

Update: Thanks to Travis: It's compiling now, but it's not working.

implicit def PersonCodecJson : CodecJson[Person] =
        casecodec3(Person.apply, Person.unapply)("name", "age", "childs")

导致无限递归和尝试解码的堆栈溢出

leads to an infinite recursion and a stack overflow trying to decode

val input = """
    [{"name": "parent1", "age": 31, "childs": [{"name": "child1", "age": 2, "childs": []}]},
     {"name": "parent2", "age": 29, "childs": []}
    ]
    """
val persons = input.decodeOption[List[Person]].getOrElse(Nil)

产生

at Person$.PersonCodecJson(main.scala:8)
at Person$.PersonCodecJson(main.scala:8)
at Person$.PersonCodecJson(main.scala:8)
at Person$.PersonCodecJson(main.scala:8)
at Person$.PersonCodecJson(main.scala:8)
at Person$.PersonCodecJson(main.scala:8)
at Person$.PersonCodecJson(main.scala:8)
at Person$.PersonCodecJson(main.scala:8)
[debug]     Thread run-main-1 exited.
[debug] Interrupting remaining threads (should be all daemons).
[debug] Sandboxed run complete..
java.lang.RuntimeException: Nonzero exit code: 1
at scala.sys.package$.error(package.scala:27)
at sbt.BuildCommon$$anonfun$toError$1.apply(Defaults.scala:1653)
at sbt.BuildCommon$$anonfun$toError$1.apply(Defaults.scala:1653)
at scala.Option.foreach(Option.scala:236)
at sbt.BuildCommon$class.toError(Defaults.scala:1653)
at sbt.Defaults$.toError(Defaults.scala:35)
at sbt.Defaults$$anonfun$runTask$1$$anonfun$apply$36$$anonfun$apply$37.apply(Defaults.scala:656)
at sbt.Defaults$$anonfun$runTask$1$$anonfun$apply$36$$anonfun$apply$37.apply(Defaults.scala:654)
at scala.Function1$$anonfun$compose$1.apply(Function1.scala:47)
at sbt.$tilde$greater$$anonfun$$u2219$1.apply(TypeFunctions.scala:42)
at sbt.std.Transform$$anon$4.work(System.scala:64)

这种对嵌套json进行解码的方法是否有效?我必须解决完全不同的问题吗?还是只是缺少一小段代码?

Is this approach to decode this nested json even valid? Do I have to tackle it completely different? Or is just another small piece of code missing?

推荐答案

您非常接近-您只需明确指定类型:

You're very close—you just need to specify the type explicitly:

object Person {
  implicit def PersonCodecJson: CodecJson[Person] =
    casecodec3(Person.apply, Person.unapply)("name", "age", "childs")
}

就像Scala不允许您在没有显式结果类型的情况下编写递归方法一样，它也不会在没有一个隐式结果类型的情况下在定义中找到隐式定义.

Just as Scala won't allow you to write a recursive method without an explicit result type, it won't find the implicit being defined inside the definition without one.

不知道这有多聪明，但是它可以工作.

Not sure how clever that is, but it works.

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