字段不完整时，用Circe解码Json [英] Decoding Json with Circe when fields are incomplete

问题描述

我有一个json格式的成绩单，里面有很多字

I have a transcript in json format with a bunch of words in it

{
     "words": [{
          "duration": 123,
          "name": "world"
          "time": 234,
          "speaker": null
      }]
}

我一直在使用Circe编码/解码Json.在这种情况下:

I have been using Circe to encode/decode Json. In this particular case:

import io.circe.generic.auto._
import io.circe.parser._

val decoded = decode[Transcript](transcriptJson)

我的ADT如下:

case class Word(
  duration: Double,
  name: String,
  time: Float,
  para: String,
  speaker: Option[String],
  key: Option[String] = None,
  strike: Option[String] = None,
  highlight: Option[String] = None
)

case class Transcript(words: List[Word])

有时单词具有"strike"或"highlight"之类的键，但很可能没有.否则，我会收到以下错误消息.

Sometimes words have keys like "strike" or "highlight", but most likely not. When it doesn't, I get the following error message.

Left(DecodingFailure([A]List[A], List(DownField(highlight), MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, MoveRight, DownArray, DownField(words))))

当单词"没有所有字段时正确解码它的最佳方法是什么?

What would be the best way to decode it properly when a "word" doesn't have all the fields?

推荐答案

正如Travis Brown在Gitter上指出的那样:

As Travis Brown pointed out on Gitter:

这将与通用扩展名保持原样:"

"this would work as-is with generic-extras:"

import io.circe.generic.extras.Configuration

implicit val config: Configuration = Configuration.default.withDefaults

(加上para和import io.circe.generic.extras.auto._的默认值)

(plus a default value for para and import io.circe.generic.extras.auto._)

这篇关于字段不完整时，用Circe解码Json的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！