Kotlin中的2D阵列 [英] 2D Array in Kotlin

问题描述

如何在Kotlin中制作2D Int数组?我正在尝试将此代码转换为Kotlin:

How do you make a 2D Int array in Kotlin? I'm trying to convert this code to Kotlin:

    int[][] states = new int[][] {
        new int[]{-android.R.attr.state_pressed}, // not pressed
        new int[] { android.R.attr.state_pressed}  // pressed
    };
    int[] colors = new int[] {
        foregroundColor,
        accentColor,
        accentColor
    };
    ColorStateList myList = new ColorStateList(states, colors);

这是我尝试的一个尝试，其中第一个2D数组不起作用，但是我让1D数组起作用:

Here is one attempt I tried, where the first 2D array didn't work, but I got the 1D array to work:

    //This doesn't work:
    var states: IntArray = intArrayOf(
        intArrayOf(-android.R.attr.state_pressed), // not pressed
        intArrayOf(android.R.attr.state_pressed)  // pressed
    );
    //This array works:
    var colors: IntArray = intArrayOf(
        foregroundColor,
        accentColor,
        accentColor
    );
    val myList: ColorStateList = ColorStateList(states, colors);

推荐答案

您正试图将IntArrays放入另一个数组中，使其成为二维. 该数组的类型不能为intArray，这就是失败的原因. 用arrayOf而不是intArrayOf包裹您的初始数组.

You are trying to put your IntArrays inside another array to make it 2-dimensional. The type of that array cannot be intArray, which is why this fails. Wrap your initial arrays with arrayOf instead of intArrayOf.

val even: IntArray = intArrayOf(2, 4, 6)
val odd: IntArray = intArrayOf(1, 3, 5)

val lala: Array<IntArray> = arrayOf(even, odd)

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