Swift 3过滤对象数组和数组元素 [英] Swift 3 filter array of objects with elements of array

问题描述

array1 = array1.filter{ $0.arrayInsideOfArray1.contains(array2[0]) }

上面的代码有效，但是我试图检查$ 0.arrayInsideOfArray1的所有元素是否与array2的所有元素匹配，而不仅仅是[0]

Code above works but I'm trying to check if all the elements of $0.arrayInsideOfArray1 match with all the elements of array2 not just [0]

示例:

struct User {
    var name: String!
    var age: Int!
    var hasPet: Bool!
    var pets: [String]!
}

var users: [User] = []

users.append(User(name: "testUset", age: 43, hasPet: true, pets: ["cat", "dog", "rabbit"]))
users.append(User(name: "testUset1", age: 36, hasPet: true, pets:["rabbit"]))
users.append(User(name: "testUset2", age: 65, hasPet: true, pets:["Guinea pigs", "Rats"]))

let petArr = ["cat", "dog", "rabbit"]

users = users.filter { $0.pets.contains(petArr[0]) }

我想要的是在petArr中列出任何宠物的任何用户！

What I want is any user that has any pet listed in the petArr!

推荐答案

一种方法是更新过滤器，以查看pets中是否有任何值位于petArr数组中:

One approach is to update your filter to see if any value in pets is in the petArr array:

users = users.filter { $0.pets.contains(where: { petArr.contains($0) }) }

第一个$0来自filter，它代表每个User.

The first $0 is from the filter and it represents each User.

第二个$0来自第一个contains，它表示当前User的pets数组中的每个宠物.

The second $0 is from the first contains and it represents each pet within the pets array of the current User.

这篇关于Swift 3过滤对象数组和数组元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！