Javascript:将字符串拆分为与数组匹配的参数 [英] Javascript: Split a string into array matching parameters
问题描述
我有一个包含数字和数学运算符(+
,x
,-
,/
)的字符串
I have a string that has numbers and math operators (+
,x
,-
, /
) mixed in it
'12+345x6/789'
我需要将其转换为由这些数学运算符分隔的数组.
I need to convert it into an array seperated by those math operators.
[12, +, 345, x, 6, /, 789]
执行此操作的简单方法是什么?
What is a simple way of doing this?
推荐答案
拆分连续的非-数字字符\D+
您获得
console.log ('12+345x6/789'.split (/\D+/))
// [ '12', '345', '6', '789' ]
如果您添加捕获组,则(\D+)
您也会获得分隔符
If you add a capture group, (\D+)
you get the separator too
console.log ('12+345x6/789'.split (/(\D+)/))
// [ "12", "+", "345", "x", "6", "/", "789" ]
如果要支持解析小数,请将正则表达式更改为/([^0-9.]+)/
-注意,上面使用的\D
等同于[^0-9]
,因此我们在这里要做的就是将.
添加到字符类中
If you want to support parsing decimals, change the regexp to /([^0-9.]+)/
- Note, \D
used above is equivalent to [^0-9]
, so all we're doing here is adding .
to the character class
console.log ('12+3.4x5'.split (/([^0-9.]+)/))
// [ "12", "+", "3.4", "x", "5" ]
还有一种编写程序其余部分的可能方式
And a possible way to write the rest of your program
const cont = x =>
k => k (x)
const infix = f => x =>
cont (f (x))
const apply = x => f =>
cont (f (x))
const identity = x =>
x
const empty =
Symbol ()
const evaluate = ([ token = empty, ...rest], then = cont (identity)) => {
if (token === empty) {
return then
}
else {
switch (token) {
case "+":
return evaluate (rest, then (infix (x => y => x + y)))
case "x":
return evaluate (rest, then (infix (x => y => x * y)))
case "/":
return evaluate (rest, then (infix (x => y => x / y >> 0)))
default:
return evaluate (rest, then (apply (Number (token))))
}
}
}
const parse = program =>
program.split (/(\D+)/)
const exec = program =>
evaluate (parse (program)) (console.log)
exec ('') // 0
exec ('1') // 1
exec ('1+2') // 3
exec ('1+2+3') // 6
exec ('1+2+3x4') // 24
exec ('1+2+3x4/2') // 12
exec ('12+345x6/789') // 2
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