计算数组中的整数和 [英] Calculating the sum of integers in an array

问题描述

我不知道我是否只是个傻瓜，很可能是很长的一天，但是这并没有达到我想要的效果，而且，我没有看到为什么.

I don't know if I'm just being a total fool, most likely I am, it's been a long day, but this isn't working as I want it to, and, well, I don't see why.

它应该能够输入11个数字，在每行上输入一个新数字，将它们添加到数组中，然后将它们加起来，但是这是行不通的.即使我要递增i，也不会停止退出循环.

It should be able to have 11 numbers entered, a new number on each line, add them to the array, then total them, yet it's just not working. It's not stopping to exit the loop, even though I am incrementing i.

有什么想法吗?

int main(void) {
 int array[10];
 int i;
 int sum = 0;
  for ( i = 0; i < 11; i++){
   scanf("%d", &array[i]);
  }
  for (i = 0; i < 11; i++) {
   sum += array[i];
  }
printf("%d", sum);

return 0;

}

推荐答案

您的数组中有10个元素，编号为0-9.您正在缓冲区中溢出，因此所有选项都关闭了.这是不确定的行为.

You have 10 elements in the array, numbered 0 - 9. You are overflowing the buffer, so all bets are off. This is undefined behaviour.

这篇关于计算数组中的整数和的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！