如何在bash中获取另一个变量? [英] How to get a variable by another one in bash?

问题描述

我在bash中有三个数组.

I have three arrays in bash.

 arr1=(arr2 arr3)
 arr2=(1 2 3 4)
 arr3=(6 7 8 9)
 #How can I get a element of arr2 by arr1? like below:
 ${${arr1[0]}[0} # To get first element in arr2

推荐答案

使用eval:

eval echo \${${arr1[0]}[0]}

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