字节溢出时实际发生了什么? [英] What actually happens when a Byte overflows?

问题描述

当字节溢出时实际发生什么?

What actually happens when a Byte overflows?

说我们有

byte byte1 = 150; // 10010110  
byte byte2 = 199; // 11000111

如果我们现在进行此添加

If we now do this addition

byte byte3 = byte1 + byte2;

我认为我们最终将得到byte3 = 94，但是实际上会发生什么呢?我是否以某种方式覆盖了其他一些内存，或者这完全无害吗?

I think we'll end up with byte3 = 94 but what actually happens? Did I overwrite some other memory somehow or is this totally harmless?

推荐答案

这很简单.它只是进行加法运算，并得到一个8位以上的数字.第九位(为1)刚刚下降"，剩下剩下的8位组成数字94.

It's quite simple. It just does the addition and comes off at a number with more than 8 bits. The ninth bit (being one) just 'falls off' and you are left with the remaining 8 bits which form the number 94.

(是的，这是无害的)

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