如何将整数钳位到某个范围? [英] How to clamp an integer to some range?

问题描述

我有以下代码:

new_index = index + offset
if new_index < 0:
    new_index = 0
if new_index >= len(mylist):
    new_index = len(mylist) - 1
return mylist[new_index]

基本上，我计算一个新索引，并使用该索引从列表中查找某些元素.为了确保索引在列表的范围内，我需要编写这2条if语句，这些语句分散在4行中.这很冗长，有点丑陋……我敢说，这很非pythonic .

Basically, I calculate a new index and use that to find some element from a list. In order to make sure the index is inside the bounds of the list, I needed to write those 2 if statements spread into 4 lines. That's quite verbose, a bit ugly... Dare I say, it's quite un-pythonic.

还有其他更简单，更紧凑的解决方案吗?(还有更多的 pythonic )

是的，我知道我可以在一行中使用if else，但是它不可读:

Yes, i know I can use if else in one line, but it is not readable:

new_index = 0 if new_index < 0 else len(mylist) - 1 if new_index >= len(mylist) else new_index

我也知道我可以将max()和min()链接在一起.它更紧凑，但是我觉得它有点晦涩难懂，如果我输入错误的话，更难发现错误.换句话说，我觉得它不是很简单.

I also know I can chain max() and min() together. It's more compact, but I feel it's kinda obscure, more difficult to find bugs if I type it wrong. In other words, I don't find it very straightforward.

new_index = max(0, min(new_index, len(mylist)-1))

推荐答案

实际上，这很清楚.许多人很快学会了它.您可以使用评论来帮助他们.

This is pretty clear, actually. Many folks learn it quickly. You can use a comment to help them.

new_index = max(0, min(new_index, len(mylist)-1))

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