javascript按子列表第二项对列表进行排序 [英] javascript sort list of lists by sublist second entry

问题描述

如何按最后一个元素的顺序对列表列表进行排序?

How can I sort a list of lists by order of the last element?

这是迄今为止我最好的尝试:

Here is my best attempt so far:

var mylist = [ [1, 'c'], [3, 'a'],  [5, 'b']];
mylist.sort(function(a,b){return a[1]-b[1];});

我对sort的呼叫无效，并且mylist保持相同的顺序.

My call to sort has not effect, and mylist remains in the same order.

推荐答案

var mylist = [ [1, 'c'], [3, 'a'],  [5, 'b']];
mylist.sort(function(a,b){return a[1].localeCompare(b[1]);});
console.log(mylist)

使用a[1].localeCompare(b[1])以升序对列表进行排序，或者使用b[1].localeCompare(a[1])进行其他排序.这样，您将比较两个字符串.您试图从另一个字符串中减去一个字符串，该字符串返回NaN.

Use a[1].localeCompare(b[1]) to sort the list in the ascending order or b[1].localeCompare(a[1]) for other way round. This way you will be comparing two strings. You were trying to subtract one string from the other which return NaN.

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