TypeError:“<" 'dict'和'dict'实例之间不受支持 [英] TypeError: '<' not supported between instances of 'dict' and 'dict'

问题描述

我在python 2.7中具有按值排序的功能，但是我试图升级到python 3.6，却收到该错误:

I had a perfectly functioning sort by value in python 2.7 but I'm trying to upgrade to python 3.6 and I get that error:

TypeError:'<' 'dict'和'dict'实例之间不支持

TypeError: '<' not supported between instances of 'dict' and 'dict'

这是我的代码

server_list = []

for server in res["aggregations"]["hostname"]["buckets"]:
    temp_obj = []
    temp_obj.append({"name":server.key})        
    temp_obj.append({"stat": server["last_log"]["hits"]["hits"][0]["_source"][system].stat})
    server_list.append(temp_obj)
    server_list.sort(key=lambda x: x[0], reverse=False)

为什么在将server_list声明为列表时将其视为命令.如何按名称属性对其进行排序?

Why it's considered as a dict when I declare my server_list as a list. How can I make it sort by my name attribute?

推荐答案

Python 2的字典排序顺序为且了解甚少.只是因为Python 2试图使所有东西都可排序而起作用.

Python 2's dictionary sort order was quite involved and poorly understood. It only happened to work because Python 2 tried to make everything orderable.

对于您的特定情况，对于具有单个键的{'name': ...}词典，排序由该单个键的值确定.

For your specific case, with {'name': ...} dictionaries with a single key, the ordering was determined by the value for that single key.

在Python 3中，字典不再可排序(以及许多其他类型)，只需使用该值作为排序键即可:

In Python 3, where dictionaries are no longer orderable (together with many other types), just use that value as the sorting key:

server_list.sort(key=lambda x: x[0]['name'], reverse=False)

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