NumPy排序函数返回None [英] NumPy sort function returns None

问题描述

我下面有一个简单的程序:

I have one simple program below:

import numpy as np

arr = np.random.randn(8)
new = arr.sort()
new1 = np.sort(arr)
print new
print new1

我希望这两个新数组与排序数组相同，但是new是None，new1是我期望的，两种排序方法之间有什么区别?

I expected the two new arrays to be the same a sorted array, but instead, new is None, new1 is what I expected, what is the difference between two methods to sort?

推荐答案

来自 numpy.ndarray.sort的文档:

就地对数组进行排序.

Sort an array, in-place.

如果要原始数组的排序副本，而不是就地排序，则应使用numpy.sort，它会返回一个副本，如您所见.

If you want a sorted copy of the original array, rather than sorting in place, you should use numpy.sort, which returns a copy, as you saw.

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