在Android Studio中使用用户输入进行气泡排序应用 [英] bubble sort app with user input in android studio
本文介绍了在Android Studio中使用用户输入进行气泡排序应用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是android编程的新手,我试图通过在一个EditText中输入数字来进行冒泡排序,排序后的数字将输出到textview上.单击输入按钮后,程序意外停止.请告诉我什么地方出了问题"谢谢.
I am new to android programming and I tried to do bubble sort by inputting numbers in one EditText and the sorted numbers will be outputted on the textview. The program has stopped unexpectedly once I click the input button. Please "tell me what is wrong" Thank you.
public class MainActivity extends AppCompatActivity {
TextView Result;
EditText Input;
Button ASButton;
int i,j,temp,num[];
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ASButton = (Button) findViewById(R.id.button);
Input = (EditText) findViewById(R.id.editText);
Result = (TextView) findViewById(R.id.textView2);
ASButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
BubbleSort();
}
});
}
public void BubbleSort() {
Spannable spn = Input.getText();
for (int i = 0; i < spn.length(); i++){
num[i] = Integer.parseInt(""+spn.charAt(i));
}
for (i = 0; i < num.length; i++) {
for (j = i + 1; j < num.length; j++) {
if (num[i] > num[j]) {
temp = num[i];
num[i] = num[j];
num[j] = temp;
}
}
}
String result = "";
for (int i = 0; i < num.length; i++){
result += num[i] + " ";
}
Result.setText(result);
}
}
推荐答案
您尚未初始化num.使用以下代码
you don't have initialized num. use following code
public void BubbleSort() {
Spannable spn = Input.getText();
num = new int[spn.length()];
int count = 0;
for (int i = 0; i < spn.length(); i++){
if((spn.charAt(i)+"").matches(".*\\d.*")){
num[i] = Integer.parseInt(""+spn.charAt(i));
count++;
}
}
for (i = 0; i < count; i++) {
for (j = i + 1; j < count; j++) {
if (num[i] > num[j]) {
temp = num[i];
num[i] = num[j];
num[j] = temp;
}
}
}
String result = "";
for (int i = 0; i < num.length; i++){
result += num[i] + " ";
}
Result.setText(result);
}
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