C ++向量排序奇数，甚至留下 [英] C++ Vector sort odd and even stay

问题描述

此代码有什么问题?我想对奇数进行排序，但还要保留它们的位置，为此设置了函数，但编译器无法通过

whats wrong about this code? I want to sort odd numbers but even stay int their places, made function for this but compilator wont pass this

有错误:

错误:必须调用对非静态成员函数的引用

error: reference to non-static member function must be called

有一个代码:

public:
std::vector<int> sortArray(std::vector<int> array)
{
   std::vector<int> sortedArray(array);
   std::sort ( sortedArray.begin() , sortedArray.end() , oddSort );
}

bool oddSort ( const int& left , const int& right ){
  if ( left % 2 && right % 2 )
    return left < right;
  else if ( left % 2 )
    return false;
  else if ( right % 2 )
    return true;
  return left < right;
}

推荐答案

Danh的评论是正确的，但这实际上是一个重复的问题.但是，目前尚无重复的答案.

Danh's comment is right, but this is actually a duplicate question. However, there are no duplicates with accepted answers yet.

所以:问题是成员函数需要一个this指针，除非它们是static.而且std::sort不会为您提供this指针，也不需要一个.因此，将其设置为static是直接的解决方案.

So: the problem is that member functions need a this pointer, unless they're static. And std::sort won't give you a this pointer, nor do you need one. So making it static is the straightforward solution.

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