调试-编程接收到的信号SIGSEGV，分段错误 [英] Debug---Program received signal SIGSEGV, Segmentation fault

问题描述

代码在这里，由G ++编译.输入N = 600000后输入.弹出一个窗口，说明 *.exe已停止工作.调试代码时，标题为 Error 的窗口表示程序在排序行时收到信号SIGSEGV，Segmentation fault..现在，我知道这是stackoverflow错误.谢谢大家！

The code is here, and it is compiled by G++. After input N=600000 and enter. A window popped out said that *.exe has stopped working. When debugging the code, a window titled Error said that Program received signal SIGSEGV, Segmentation fault. when come to sort line. Now, I know it's stackoverflow error.Thank you, all guys!

#include <iostream>
#include <stdlib.h>     /* srand, rand */
#include <algorithm>

int main (int argc, char *argv[]) {

int N;
std::cout << "N:";
int a[N];
for(int i = 0; i < N; i++){
    a[i] = rand()%N;
}
std::sort(a,a+N);
std::cout << "The "<<N/2<<"th smallest number is: " << a[N/2-1] <<"\n";
return 0;
}

推荐答案

据我所知，具有运行时大小的数组是C99的功能，仅在某些C ++编译器中作为扩展提供.将其切换为std::vector<int> a(N);，代码应该可以正常工作.

As far as I know, an array with a run-time size is a C99 feature and only provided as extension in some C++ compilers. Switch this to a std::vector<int> a(N); and the code should work.

顺便说一句:

• 排序不是找到第N个最小数字的最快方法.
• 请考虑克里斯的评论，您的问题缺少必要的信息.另外，缩进并清理代码，我认为没有必要运行循环.
• 您还可以从IOStreams检索输入，无需使用scanf():while (cin >> N) { /*use n*/ }.

• Sorting this is not the fastest way to find the N-th smallest number.
• Please consider Chris' comment, that your question lacks the necessary information. Also, indent and clean up your code, I don't think that it's necessary to run a loop.
• You can also retrieve input from IOStreams, no need to use scanf(): while (cin >> N) { /*use n*/ }.

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