将Unix/Linux时间转换为Windows FILETIME [英] Convert Unix/Linux time to Windows FILETIME

问题描述

我再次从Windows迁移到Linux，我必须将Windows移植到计算NTP时间的函数.看起来很简单，但格式为Windows FILETIME格式.我有点知道有什么区别，但是到目前为止，我无法正确地将Linux时间转换为Windows filetime格式.有人对如何执行此操作有任何想法吗?

I am once again going from Windows to Linux, I have to port a function from Windows to Linux that calculates NTP time. Seems simple but the format is in Windows FILETIME format. I sort of have an idea what the differences are but so far I can not correctly convert my Linux time to the windows filetime format. Does anyone have any ideas on how to do this?

我看过一些有关如何执行此操作的文章，但是它们都使用win32函数，而我不能使用它们！如果没有意义，我可以发布Windows代码，谢谢.

I have seen some articles on how to do this but they all use win32 functions and I can't use them! I can post the windows code if this makes no sense, thanks.

他们还采用当前时间，并从1900年1月1日开始将其减去以获得NTP的增量，我想在Linux中我只是将const unsigned long EPOCH = 2208988800UL加到我的时间上以获得此结果?

They also take the current time and subtract it from January 1st 1900 to get the delta to find NTP, I would assume in Linux I just add the const unsigned long EPOCH = 2208988800UL to my time to get this result?

谢谢.

推荐答案

-6 ). 2.html"rel =" nofollow noreferrer> gettimeofday() .因此，以下C函数可以完成这项工作:

The Microsoft documentation for the FILETIME structure explains what it is. The basic idea is that a Windows FILETIME counts by steps of 10^-7 seconds (100-nanosecond intervals) from 1 Jan 1601 (why 1601? no idea...). In Linux you can obtain time in microseconds (10^-6) from 1 Jan 1970 using gettimeofday(). Thus the following C function does the job:

#include <sys/time.h>
/**
 * number of seconds from 1 Jan. 1601 00:00 to 1 Jan 1970 00:00 UTC
 */
#define EPOCH_DIFF 11644473600LL

unsigned long long
getfiletime() {
    struct timeval tv;
    unsigned long long result = EPOCH_DIFF;
    gettimeofday(&tv, NULL);
    result += tv.tv_sec;
    result *= 10000000LL;
    result += tv.tv_usec * 10;
    return result;
}

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