使用str.format截断字符串的开头 [英] Truncate beginning of string with str.format

问题描述

我想在右边插入一个字符串，但其开头应被截断而不是结尾.

I'd like to allign a string to the right but have its beginning be truncated instead of its end.

我尝试过:

my_str = '01234567890'
print "{0:>4.4}".format(my_str)

输出:

'0123'

所需的输出:

'7890'

有没有办法用format做到这一点，或者我必须在送入弦线之前先剪掉弦线?

Is there a way to do this with format or do I have to cut the string before feeding it?

推荐答案

您可以将字符串的反向用作输入，然后再次反向输出.

You can use the reverse of the string as input and reverse again the output.

my_str = "01234567890"
new_str = "{:4.4}".format(my_str[::-1])
desired_output = new_str[::-1]

print(my_str[::-1])
print(new_str)
print(desired_output)

输出:

09876543210
0987
7890

请注意，在此处(StackOverflow问题37974565 )，如果输入的字符串不能更改(子字符串，反向)，则可以提供解决方案.

Note that a more complex way is described here (StackOverflow question 37974565), which offers a solution if the input string may not be changed (substring, reverse).

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