Prolog-生成适合给定范围的数字 [英] Prolog - generating numbers fitting given range

查看:158
本文介绍了Prolog-生成适合给定范围的数字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想使用以下谓词:

range(X,0,5)
range(X,4,200)
range(X,-1000000,1000000)
dom_range(X,-1000000,1000000)

含义:

range(X,0,5) :- member(X,[0,1,2,3,4,5]).
range(X,4,200) :- member(X,[4,5,6...198,199,200]).
range(X,-1000000,1000000) :- member(X,[-1000000,...,1000000]).
dom_range(X,-1000000,1000000) :- domain(X, [-1000000,...,1000000]).

如何在Prolog中很好地编码(考虑解决方案的性能-递归深度等)?

How to code it in Prolog nicely (taking solution performance into account - depth of recursion etc) ?

解决方案有望在GNU-Prolog上运行.

Solution is expected to run on GNU-Prolog.

P.S.受到此问题启发的问题.

推荐答案

SWI-Prolog具有谓词/3之间.因此,您可以像在(0,5,X)之间那样调用它,以获取如上所示的结果.这个谓词看起来像是用C实现的.

SWI-Prolog has the predicate between/3. so you would call it like between(0,5,X) to get the results you showed above. This predicate looks like this is implemented in C though.

如果我们必须以纯序言形式编写它(并且速度和空间不是一个因素),则可以尝试以下操作.

If we have to write it in pure prolog (and speed&space is not a factor), you could try this following.

range(Low, Low, High).
range(Out,Low,High) :- NewLow is Low+1, range(Out, NewLow, High).

这篇关于Prolog-生成适合给定范围的数字的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆