如何删除json对象的键和值? [英] how to remove json object key and value.?

问题描述

我有一个json对象，如下所示.我想使用以下无效的代码删除"otherIndustry"条目及其值.

I have a json object as shown below. where i want to delete the "otherIndustry" entry and its value by using below code which doesn't worked.

var updatedjsonobj = delete myjsonobj['otherIndustry'];

如何删除Json对象特定的键及其值. 以下是我要删除"otherIndustry"键及其值的示例json对象.

How to remove Json object specific key and its value. Below is my example json object where i want to remove "otherIndustry" key and its value.

var myjsonobj =  {
      "employeeid": "160915848",
      "firstName": "tet",
      "lastName": "test",
      "email": "[e-mail]",
      "country": "Brasil",
      "currentIndustry": "aaaaaaaaaaaaa",
      "otherIndustry": "aaaaaaaaaaaaa",
      "currentOrganization": "test",
      "salary": "1234567"
    };
delete myjsonobj ['otherIndustry'];
console.log(myjsonobj);

其中日志仍会打印相同的对象，而不会从对象中删除"otherIndustry"条目.

where the log still prints the same object without removing 'otherIndustry' entry from the object.

推荐答案

delete运算符用于remove对象property.

delete运算符不返回新对象，仅返回boolean: true 或 false .

delete operator does not returns the new object, only returns a boolean: true or false.

另一方面，在解释器执行var updatedjsonobj = delete myjsonobj['otherIndustry'];之后，updatedjsonobj变量将存储boolean 值.

In the other hand, after interpreter executes var updatedjsonobj = delete myjsonobj['otherIndustry']; , updatedjsonobj variable will store a boolean value.

如何删除Json对象特定的键及其值?

How to remove Json object specific key and its value ?

您只需要知道属性名称即可从对象的属性中删除它.

You just need to know the property name in order to delete it from the object's properties.

delete myjsonobj['otherIndustry'];

let myjsonobj = {
  "employeeid": "160915848",
  "firstName": "tet",
  "lastName": "test",
  "email": "[e-mail]",
  "country": "Brasil",
  "currentIndustry": "aaaaaaaaaaaaa",
  "otherIndustry": "aaaaaaaaaaaaa",
  "currentOrganization": "test",
  "salary": "1234567"
}
delete myjsonobj['otherIndustry'];
console.log(myjsonobj);

如果要在知道值的情况下删除key，则可以使用Object.keys函数，该函数返回给定对象自己的可枚举属性的数组.

If you want to remove a key when you know the value you can use Object.keys function which returns an array of a given object's own enumerable properties.

let value="test";
let myjsonobj = {
      "employeeid": "160915848",
      "firstName": "tet",
      "lastName": "test",
      "email": "[e-mail]",
      "country": "Brasil",
      "currentIndustry": "aaaaaaaaaaaaa",
      "otherIndustry": "aaaaaaaaaaaaa",
      "currentOrganization": "test",
      "salary": "1234567"
}
Object.keys(myjsonobj).forEach(function(key){
  if(myjsonobj[key]==value)
    delete myjsonobj[key];
});
console.log(myjsonobj);

这篇关于如何删除json对象的键和值?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！