显示来自服务器响应的错误消息 [英] Show Error Message from Server Response

问题描述

我在jqGrid上遇到一些问题.

I have some problems with jqGrid.

我添加了一种验证用户输入的方法.如果该部门存在，则会显示一条警告消息，部门已存在！"

I've added a method that validates users input. If the department exist then it will show a warning message, "Department is Exist!"

这是我的jqGrid代码:

Here's my jqGrid code:

afterSubmit: function(response, postdata){
                    var res = $.parseJSON(response.responseText);
                    if (res === "1") {
                        return [false,"Department Already Exist"];
                    } else {
                        return [true,"Sucess"];
                    }
                }

我的php添加方法:

if($oper == 'add') {
 $deptid = $_POST['idms_department'];
 $deptnm = $_POST['department'];
 if(checkUser($deptnm) == "FALSE"){
   return "1";
 } else {
   $ins = "INSERT INTO ms_department(department) VALUES('$deptnm')";
    if(mysql_query($ins)){
        "Success INSERT msDept";
    } else {
        die("Failed : " .mysql_error());
    }
}
     mysql_close();
} else .... (another operation)

该消息本身未显示.您如何正确使用afterSubmit方法? 谢谢

The message itself is not showing. How do you use the afterSubmit method properly? thanks

更新

我将方法更改为

  crudMessage = function(response,postdata){
                var res   = response.responseText; // response text is returned from server.
                 if (res === "1") {
                    return [false,"Department Already Exist"];
                } else {
                    return [true,"Sucess"];
                }
             }

然后从jqgrid主体中删除afterSubmit并将此行添加到jqgrid导航中:

then removing the afterSubmit from the jqgrid body and add this line into the jqgrid navigation:

 jQuery("#departments").jqGrid('navGrid','#pager-departments',{edit:true,add:true,del:true}, {closeAfterEdit: true},{beforeShowForm: function(form) { $('#idms_department', form).hide(); },closeAfterAdd:true},{afterSubmit: crudMessage},{closeAfterSearch:true},{});

这是最新的php语法:

here's newest php syntax:

 include 'configuration.php';

 function checkDepartment($department){
   $query = "SELECT department FROM ms_department WHERE department ='$department' LIMIT 1";
   $result= mysql_query($query);
   return mysql_num_rows($result);
}

if($oper == 'add') {
 $deptid = $_POST['idms_department'];
 $deptnm = $_POST['department'];
 if(checkDepartment($deptnm) == 1){
      echo '1';
  } else {
    $ins = "INSERT INTO ms_department(department) VALUES('$deptnm')";
     if(mysql_query($ins)){
        "Success INSERT msDept";
       } else {
        die("Failed : " . mysql_error());
    }
  }
   mysql_close();
 } else 
   if($oper == 'edit'){ ....

推荐答案

在您的代码中，为什么要使用res.insertStatus?从您提供的PHP代码片段中，您似乎想编写:

In your code, why are you expecting res.insertStatus? From the snippet of PHP code that you provided, it seems you would want to write:

var res = $.parseJSON(response.responseText);
if (res === "User Already Exist!") {

或者也许我缺少了什么?您是否尝试过调试代码?

Or maybe I am missing something? Have you tried debugging your code?

那应该解释为什么alert没有出现.

That should explain why the alert is not appearing.

根据 jqGrid表单文档，其价值是多少编辑:

提交后 从服务器收到响应后触发.通常用于显示服务器的状态(例如，数据成功保存或出于服务器端编辑原因而取消保存).接收从请求返回的数据和id = value1，value2类型的已发布值的数组作为参数.

afterSubmit fires after response has been received from server. Typically used to display status from server (e.g., the data is successfully saved or the save cancelled for server-side editing reasons). Receives as parameters the data returned from the request and an array of the posted values of type id=value1,value2.

使用此事件时，应返回包含以下项目的数组[success, message, new_id]其中

When used this event should return array with the following items [success, message, new_id]where

成功是布尔值，如果为true，则继续处理；如果为false，则出现错误消息，并停止所有其他处理. (如果成功为真，则忽略消息).

success is a boolean value if true the process continues, if false a error message appear and all other processing is stopped. (message is ignored if success is true).

new_id可用于在网格中设置新的行ID. afterSubmit:函数(响应，后置数据) { … 返回[成功，消息，new_id] }

new_id can be used to set the new row id in the grid when we are in add mode. afterSubmit : function(response, postdata) { … return [success,message,new_id] }

根据这些文档，您的最终代码应删除alert，而直接使用jqGrid:

Based on these docs, your final code should remove the alert and just use jqGrid directly:

if (res === "User Already Exist!") {
    return [false, "TODO: put your error message here"];
} 

这篇关于显示来自服务器响应的错误消息的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！