使用underscore.js显示来自Yahoo Finance的Ajax结果 [英] Displaying ajax results from yahoo finance using underscore.js

问题描述

脚本已成功检索数据，但是我无法使用underscore.js获取要显示的行"的结果.特定的故障点是"var = resultContentTemplate".无法解决这个问题.

Script is successfully retrieving data but I can not get the results of the "row" to display using underscore.js. The specific point of failure is the "var = resultContentTemplate". Can not figure this out.

$(document).ready(function(){
var symbols = symbols || ['GOOG','A','AA','AAN'];
var yqlUrl = "http://query.yahooapis.com/v1/public/yql";
var historicalUrl = 'http://finance.yahoo.com/d/quotes.csv';

var queryTemplate = _.template("select * from csv where url='" + historicalUrl + "?s=<%= symbol %>&f=n0s0l1' and columns='name,symbol,LastTradePriceOnly'");

var resultPlaceholderTemplate = _.template(
  '<li id="<%= id %>">Please wait, Loading quotes...</li>');


var resultContentTemplate = _.template(
  '<ul>'
  + '<li><% _.each(results, function(row) { %>'
  + '<%=row.name %>'
  + '<%=row.symbol %>'
  + '<%=row.LastTradePriceOnly %>'
  + '<% }); %>'
  + '</li>'
  + '</ul>');

// display the results of the query, replacing the 'loading' placeholder
function displayResult(id, queryResult, symbol) {
  var resultsAsHtml = resultContentTemplate({results: queryResult.row, symbol: symbol});
  $('#' + id).html(resultsAsHtml);
}

_.each(symbols, function(symbol) {

    var resultId = _.uniqueId();

    // lay down a placeholder
    $('#resultContainer').append(resultPlaceholderTemplate({id:resultId, symbol:symbol}));

    $.ajax({
      url: yqlUrl,
      data: {q: queryTemplate({symbol:symbol}), format: 'json'},
      context: $('#resultContainer')
    }).done(function(output) {
      console.log(output);
      var response = _.isString(output) ? JSON.parse(output) : output;
      displayResult(resultId, response.query.results, symbol);
    }).fail(function(err) {
      console.log('the thing failed with an error');
      console.log(err.responseText);
    });

});

});

推荐答案

请参见 http://jsfiddle.net/mpBMK/

您的代码对每个符号发出一个ajax请求.因此，将为每个符号调用displayResult，而queryResult参数只有一个子级，即该符号的行.

Your code is making one ajax request per symbol. Hence, displayResult is called for each symbol, and queryResult parameter has only one child, the row for that symbol.

resultContentTemplate已经获取了单行，因此您不应该遍历结果.相反:

The resultContentTemplate already gets the single row so you shouldn't iterate over results. Instead:

var resultContentTemplate = _.template(
'<ul><li><%=result.name %><%=result.symbol %><%=result.LastTradePriceOnly %></li></ul>');

...
//in displayResult(...) which is called once per symbol
var resultsAsHtml = resultContentTemplate({result: queryResult.row, symbol: symbol});

通过提琴弄清楚问题是什么以及如何解决.

It should be clear by the fiddle what the issue was and how it can be fixed.

这篇关于使用underscore.js显示来自Yahoo Finance的Ajax结果的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！