如何正确编码完整的http url字符串? [英] how do I encode a complete http url String correctly?

问题描述

我从用户那里获得了一个url字符串，并希望将其转换为合法的http url:

I get a url string from a user and would like to transform it to a legal http url:

" http://one.two/three?four 五"应该变成" http://one.two/three?four％20five "

"http://one.two/three?four five" should turn into "http://one.two/three?four%20five"

但是，URLEncoder却无济于事，因为它会编码整个字符串(包括合法的://").

however, URLEncoder does not help, as it encodes the entire string (including the legal "://").

帮助?

推荐答案

使用外部库:

import org.apache.commons.httpclient.util.URIUtil;
String myUrl_1= "http://one.two/three?four five";
System.out.println(URIUtil.encodeQuery(myUrl_1));

输出:

http://one.two/three?four%20five

或

String webResourceURL = "http://stackoverflow.com/search?q=<script>alert(1)</script> s";
System.out.println(URIUtil.encodeQuery(webResourceURL));

输出:

http://stackoverflow.com/search?q=%3Cscript%3Ealert(1)%3C/script%3E%20s

与Maven的依赖关系

And the Maven dependency

<dependency>
    <groupId>commons-httpclient</groupId>
    <artifactId>commons-httpclient</artifactId>
    <version>3.1</version>
</dependency>

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