7zipsharp提取/解压缩流到流 [英] 7zipsharp extracting/decompressing stream to stream

问题描述

我正在使用sevenzipsharp库: http://sevenzipsharp.codeplex.com/

I am using sevenzipsharp library: http://sevenzipsharp.codeplex.com/

我在巫婆中提出了类似的问题，当时我正在使用线程在同一时间压缩和解压缩流，巫婆i由于意识到这一点已被删除，因此无法完成.但是我的问题仍然存在.我如何解压缩/解压压缩流，而不是解压缩到文件，而是解压缩到另一个流.我在以下位置搜索了sevenzipsharp创建者提供的示例: http://sevenzipsharp.codeplex .com/SourceControl/latest#SevenZipTest/Program.cs ，可悲的是我没有找到有效的示例来证明自己的目标.

I made a similar question in witch i was compressing and decompressing a stream at the "same time" using threads, witch i since have deleted due to realizing that, that cannot be done. However my question still stands. How do i decompress/extract a compressed stream, not to a file, but to another stream. I have searched the examples provided by the sevenzipsharp creators in : http://sevenzipsharp.codeplex.com/SourceControl/latest#SevenZipTest/Program.cs , sadly i have found no valid example to what i am trying to achieve.

我已经用这种方法压缩了流:

I have compressed the stream with this method:

            SevenZip.SevenZipCompressor compressor = new SevenZip.SevenZipCompressor();
            compressor.CompressionMethod = SevenZip.CompressionMethod.Lzma2;
            compressor.CompressionLevel = SevenZip.CompressionLevel.Ultra;
            compressor.CompressStream(stream,output_compressed);

我尝试过:

            using (var tmp = new SevenZipExtractor(compressed))
            {
                tmp.ExtractFile(1, File.Create(@"D:\lel.txt"));
            }

推荐答案

我在编写此问题时找到了解决方案，所以我将自己为可能遇到此问题的其他人回答.

I found the solution while i was writing this question, so i will answer it myself for other people that might come across this problem.

"ExtractFile"需要2个参数，数字1是存档内文件的索引，数字2是输出流或文件.

The 'ExtractFile' is expecting 2 parameters, number 1 is the index of the file inside the archive, number 2 is the output stream or file.,

但是，当声明SevenZipExtractor时，您提供的不是压缩文件，而是像我一样已经在内存中的压缩流，并且只有一个文件，第一个参数(索引)必须为0.

but, when declaring SevenZipExtractor you provide it with not an archive but a compressed stream that is already in memory like i did, and there is nothing but just one file, the 1st parameter(index) must be 0.

最终代码应如下所示:

            using (var tmp = new SevenZipExtractor((stream_to_compress)))
            {
                tmp.ExtractFile(0,output_stream ));
            }

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