如何遍历哈希数组并以单个字符串返回值? [英] How do I iterate over an array of hashes and return the values in a single string?

问题描述

很抱歉，如果这很明显，我只是不明白.如果我有一系列的哈希值，例如:

Sorry if this obvious, I'm just not getting it. If I have an array of hashes like:

people = [{:name => "Bob", :occupation=> "Builder"}, {:name => "Jim", :occupation =>
"Coder"}]

我想遍历数组并输出类似"Bob:Builder"的字符串.我该怎么办?我知道如何进行迭代，但是我仍然有点迷路.现在，我有:

And I want to iterate over the array and output strings like: "Bob: Builder". How would I do it? I understand how to iterate, but I'm still a little lost. Right now, I have:

people.each do |person|
  person.each do |k,v|
    puts "#{v}"
  end
end

我的问题是我不了解如何返回两个值，而仅返回每个值.我想念什么?

My problem is that I don't understand how to return both values, only each value separately. What am I missing?

谢谢您的帮助.

推荐答案

在这里:

puts people.collect { |p| "#{p[:name]}: #{p[:occupation]}" }

或者:

people.each do |person|
  puts "#{person[:name]}: #{person[:occupation]}"
end

在回答有关访问数组中元素值的更一般的查询时，您需要知道people是一个哈希数组.哈希具有keys方法和values方法，分别返回键和值.考虑到这一点，一个更通用的解决方案可能类似于:

In answer to the more general query about accessing the values in elements within the array, you need to know that people is an array of hashes. Hashes have a keys method and values method which return the keys and values respectively. With this in mind, a more general solution might look something like:

people.each do |person|
  puts person.values.join(': ')
end

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