在Unity中重复音频剪辑，间隔越来越小 [英] Repeat audio clip in Unity, with increasingly smaller intervals

问题描述

我希望倒数计时器随着时间的倒数而更快地滴答. 滴答声"是一个很短的音频剪辑.

I want a countdown timer to tick faster as the time counts down. the 'tick' is a very short audioclip.

我已经有了计时器，它每帧都会调用pl​​ayTickManager().

I've got the timer working which calls playTickManager() every frame.

但是，通过此实现，在取消/重新调用的某些转换中，滴答之间的间隙不一致或重叠，从而导致滴答声不自然.

However with this implementation, at some transitions of cancel/re-invoke, the gap between ticks is inconsistent or overlaps causing an unnatural sounding tick.

有没有更好的方法来实现此目的而又不加速实际的音频剪辑，从而保持音调等?

Is there a better way to implement this without speeding up the actual audioclip, thus maintaining pitch etc?

// This is called every frame by the 'timer' script as it counts down to 0. 
// 'seconds' is a float.

void playTickManager()
{
    Debug.Log(seconds);
    if (seconds >= 20 && tickPlaySpeed != 1)
    {
        InvokeRepeating("playTickAudio", 1f, 1f);
        tickPlaySpeed = 1;
    }
    else if (seconds >= 16 && seconds < 20 && tickPlaySpeed != 2)
    {
        CancelInvoke("playTickAudio");
        InvokeRepeating("playTickAudio", 0f, .85f);
        tickPlaySpeed = 2;
    }
    else if (seconds >= 12 && seconds < 16 && tickPlaySpeed != 3)
    {
        CancelInvoke("playTickAudio");
        InvokeRepeating("playTickAudio", 0f, .7f);
        tickPlaySpeed = 3;
    }
    else if (seconds > 8 && seconds < 12 && tickPlaySpeed != 4)
    {
        CancelInvoke("playTickAudio");
        InvokeRepeating("playTickAudio", 0f, .55f);
        tickPlaySpeed = 4;
    }
    else if (seconds >= 4 && seconds < 8 && tickPlaySpeed != 5)
    {
        CancelInvoke("playTickAudio");
        InvokeRepeating("playTickAudio", 0f, .4f);
        tickPlaySpeed = 5;
    }
    else if (seconds > 0 && seconds < 3 && tickPlaySpeed != 6)
    {
        CancelInvoke("playTickAudio");
        InvokeRepeating("playTickAudio", 0f, .25f);
        tickPlaySpeed = 6;
    }
    else if(seconds <= 0)
    {
        CancelInvoke("playTickAudio");
        tickPlaySpeed = 0;
    }
}

void playTickAudio()
{
    AudioSource.PlayClipAtPoint(tickAudio, gameObject.transform.position, 1f);
}

推荐答案

这是学习非常常见的模式的好机会.

This is a good chance to learn a very common pattern.

这是软件中的 再次打电话给自己" 模式.

This is the "call yourself again" pattern in software.

请注意，这在游戏中非常普遍-尤其是每种武器类型都使用再次致电自己"图案. (简而言之，您不需要使用"invokeRepeating"之类的东西，因为您需要对触发循环进行更多控制.)

Note that this is very, very common in games - notably every type of weapon uses the "call yourself again" pattern. (In short, you don't use something like "invokeRepeating" since you need more control over the firing loop.)

因此，请尝试此教学示例:

So try this ... teaching example:

private float gapToNext;

private void ExcitingCountdown()
  {
  gapToNext = 2.5f;
  PlayOneStep();
  }

private void PlayOneStep()
  {
  if (gapToNext < 0.01f) return;
  YourBeepSound.Play();
  gapToNext = gapToNext - 0.1f;
  Invoke("ExcitingCountdown", gapToNext);
  }

简单吧?

请注意，实际上，您的代码如下所示:

Note that in reality, your code would look like this:

只需调整ExcitingCountdown中的值即可获得所需的探测结果.

Just adjust the values in ExcitingCountdown to get the sounding result you want.

private float gapToNext;
private int safetyCounter;

void Start()
  {
  ExcitingCountdown();
  }

private void ExcitingCountdown()
  {
  gapToNext = 2.5f;
  safetyCounter = 30;
  PlayOneStep();
  }

private void PlayOneStep()
  {
  if (gapToNext < 0.05f || safetyCounter<0)
    {
    Debug.Log("we're done...!");
    return;
    }
  
  YourBeepSound.Play();
  
  gapToNext = gapToNext * 0.85f;
  --safetyCounter;

  Debug.Log("gap is now " +gapToNext.ToString("f4"));

  Invoke("ExcitingCountdown", gapToNext);
  }

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