如何使用URL打开应用程序? [英] How to open application using URL?

问题描述

我已经实现了所有必需的条件，但是没有成功.我想从浏览器中打开应用程序-但不能仅使用 URL架构(如回调").

I have implemented all the required things but had no success. I want to open the application from browser - but not with just URL schema like a "callback".

我有类似" http://11.11.21.114:8081的内容/signup/callback?signupCode = 123?id = 20 "，那么如何识别此URL来打开我的应用程序?

I have something like "http://11.11.21.114:8081/signup/callback?signupCode=123?id=20" so how can I identify this url to open my application?

推荐答案

使用通用链接

但它仅适用于Apple网站应可访问的公共网站URL.

您唯一需要做的就是拥有https服务器并有权上传相关的域文件.

The only thing you need is to have https server and access to upload a associated domains file.

当您支持通用链接时，iOS 9用户可以点击指向您的链接 网站并无缝重定向到您已安装的应用程序，而无需 通过Safari浏览.如果您的应用未安装，请点击链接 您的网站会在Safari中打开您的网站.

When you support universal links, iOS 9 users can tap a link to your website and get seamlessly redirected to your installed app without going through Safari. If your app isn’t installed, tapping a link to your website opens your website in Safari.

Apple链接:=> 支持通用链接

Apple Link : => Support Universal Links

遵循这个不错的教程:=>

Follow this nice tutorial : => Universal Link

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