Visual Studio代码:程序具有多个定义的入口点 [英] Visual Studio Code: Program has more than one entry point defined

问题描述

我使用 Visual Studio代码 .该项目包含两个.cs文件，分别是 Addition.cs 和 Substraction.cs .这两个文件都包含 main()函数，并且两个文件都包含两个不同的程序.

I created a C# project using Visual Studio Code. This project contains two .cs files, Addition.cs and Substraction.cs. Both files contain a main() function and both files contain two different programs.

代码:

using System;

namespace Example
{
    class Addition
    {
        static void Main(string[] args)
        {
            int sum = 3 + 2;
            Console.WriteLine(sum);
        }
    }
}

Substraction.cs 文件中的

代码

Code in the Substraction.cs file

using System;

namespace Example
{
    class Substraction
    {
        static void Main(string[] args)
        {
            int sub = 3 - 2;
            Console.WriteLine(sub);
        }
    }
}

我想一个接一个地测试这两个程序，但是当我这样做的时候

I want to test both the programs one by one, but when I do

"dotnet运行"

"dotnet run"

由于上述错误而失败.

我知道，因为同一项目中有两个main()函数(入口点)会导致此错误，但这可以在Visual Studio中通过设置启动项目来克服.

I know because of two main() functions (entry points) in the same project creating this error, but this can be overcome in Visual Studio by setting up a startup project.

我正在使用 Visual Studio代码，在这里我无法设置启动项目.

I am using Visual Studio Code, where I am unable to setup a startup project.

是否可以在Visual Studio Code中为C#项目设置入口点?

Is there a way to setup entry point for a C# project in Visual Studio Code?

推荐答案

如果两个入口点都在同一个项目中，则设置启动项目将无济于事.您需要设置启动 object .

If both entry points are in the same project, setting the startup project wouldn't do anything anyway. You need to set the startup object.

这可以在完整版本的Visual Studio中的项目属性对话框(在应用程序"下查找启动对象")中完成，也可以通过设置Project/PropertyGroup/StartupObject在.csproj文件中完成:

This can be done in the project properties dialog in a full version of Visual Studio (look for "Startup object" under Application), or in the .csproj file by setting Project/PropertyGroup/StartupObject:

<StartupObject>Example.Addition</StartupObject>

或者考虑使用一个带有命令行参数的Main()入口点.

Alternatively consider using a single Main() entry point which takes a command-line argument.

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