Zapier CLI动态下拉列表，如何将多个值设置为bundle.inputData [英] Zapier CLI Dynamic Dropdown, how to set multiple values to bundle.inputData

问题描述

当前正在构建Zapier应用程序，但在尝试从动态下拉列表传递信息时遇到了阻止程序.

Currently building a Zapier app but running into a blocker when trying to pass information from a dynamic dropdown.

理想情况下，只要有人选择一项，我希望能够将数据对象设置为bundle.inputData. 文档仅提供了单一价值解决方案，但想知道是否有人知道一个解决方案?

Ideally, I want to be able to set an object of data to bundle.inputData whenever someone selects an item. Thedocs only provide a single value solution, but wondering if anybody knows of a solution to this?

问题示例:

//User Data
[
  {id:1, name: Tommy, email: [e-mail]},
  {id:2, name: Bill, email: [e-mail]},
  {id:3, name: Greg, email: [e-mail]}
]

//Input Field as part of the operation object
inputFields: [
      {
        key: 'users',
        required: true,
        label: 'Select user to notify',
        dynamic: 'users.email.name',
      },
]

我希望能够将name和email都作为bundle.inputData的一部分发送，而不是在用户选择项目时回传email.

Instead of passing back an email when a user selects an item, I want to be able to send both name and email as part of the bundle.inputData.

任何想法将不胜感激！

Any ideas would be greatly appreciated!

推荐答案

解决方案: 在触发器中将名称/电子邮件组合为字符串，并在发出最终HTTP请求时将其分开.

Solution: Combine Name/Email as a string in trigger and separate when making final HTTP request.

示例:

const combineUserEmail = (name, email) => `${name}/${email}`;

const triggerUsers = async(z, bundle) =>{
  const response = await z.request({
     url: https://blahblah.com/users
  });
  const users = z.JSON parse(response.content);
  const results = users.map((user, i) =>({id: i, user: combineUserEmail(item.name, item.email)})
}

这篇关于Zapier CLI动态下拉列表，如何将多个值设置为bundle.inputData的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！