盘点编号(HC11) [英] Counting number (HC11)
问题描述
我仍在使用此MC
现在，我要在给定数组中对正/负数和0进行计数.在c语言中，我做了这样的事情，并且效果很好:
Now i want to count positive/negative numbers and 0's in a given array. In c, i did something like this and it worked perfectly:
int A[15], pos, neg, nul, i;
[...]
pos = 0;
neg = 0;
nul = 0;
for for (i = 0; i < 15; i++) {
if (A[i] > 0) {
pos++;
}
if (A[i] < 0) {
neg++;
}
if (A[i] == 0) {
nul++;
}
}
因此，下一步是进行类似的操作，但是在汇编代码中，我正在考虑以下问题:
So, the next step is to make something similar but in assembly code, i was thinking about this:
RWM EQU $0
ROM EQU $C000
RESET EQU $FFFE
QUANTITY EQU 200
ORG RWM
POSITIVES RMB
NEGATIVES RMB
ZEROS RMB
ORG ROM
Main:
END BRA END
ARRAY DW 1,4,8,-87,0,0,1,4,5,8,7,4,4,1,-9
ORG RESET
DW Main
我有点困惑，因为我需要考虑 最坏的情况，我的意思是:全部为正，或全部为负，或全部为零. 所以，我应该根据要定义的信息来定义变量大小 已保存. 我认为数组的末尾应为ARRAY + QUANTITY-1.
i'm a little confused right here because i would need to consider the worst cases, i mean: all are positive, or all negative or all zero. So, i should define variable sizes according to the information to be saved. I think the end of the array should be ARRAY + QUANTITY-1.
EDIT#1:
在这种情况下，我想获得此输出:
For this case i would like to obtain this output:
由于数组包含以下元素:
Since th ARRAY contains these elements:
1,4,8,-87,0,0,1,4,5,8,7,4,4,1,-9
我应该得到以下输出:
POSITIVES 11
NEGATIVES 2
ZEROS 2
但是请记住:
我必须考虑最坏的情况，即:所有人都是积极的，或者都是 负数或全零
i must consider the worst cases, i.e: all are positive, or all negative or all zero
另一种情况:
假设我要获取存储在特定数组中的所有元素的绝对值.
Suppose that i want to obtain the absolute values of all the elements that are stored in a specific array.
我可以使用'C'来实现，我的意思是，我可以执行以下操作:
I can achieve that using 'C',i mean, i could perform something like this:
#include <stdio.h>
#include <math.h>
int absolute(int *array, int N);
int main()
{
int array[16] = {0,1,2,3,-4,5,6,7,-8,9,-10,11,12,13,14,20};
int ray[16];
int i;
for ( i = 0; i < 16; i++ )
ray[i]=absolute(array,16);
printf("the absolute value is %d\n", ray[i]);
return 0;
}
int absolute(int *array, int N)
{
int i;
for(i=0; i<N; i++)
if (array[i]<0)
array[i] = array[i] * (-1);
}
我试图在汇编中做到这一点(使用68hc11指令)
RWM EQU $0
ROM EQU $C000
RESET EQU $FFFE
ORG RWM
ABSOLUTE RMB
ORG ROM
Start:
END BRA END
ARRAY DW 4,144,447,-14,-555,-1147
ORG RESET
DW Start
我想将 ARRAY
I want to store inside ABSOLUTE all the absolute elements from ARRAY
PS:我尚未定义绝对尺寸
PS: i have not defined the size for ABSOLUTE
我想在ABSOLUTE中看到这些值:
I would like to see these values inside ABSOLUTE:
4,144,447,14,555,1147(无符号数字)
4,144,447,14,555,1147 (UNSIGNED NUMBERS)
推荐答案
在您的示例中，将QUANTITY的定义定义为200似乎毫无意义，因为您对数组进行了硬编码，因此无论QUANTITY是什么，它都具有已知数量的元素.说.最好让汇编程序将QUANTITY定义为实际的元素数量，如下所示(但在我的基于ASM11的示例中未使用).
The definition of QUANTITY as 200 seems pointless in your example because you hard code your array so it has a known number of elements regardless of what QUANTITY says. It would be better to have the assembler define QUANTITY to the actual number of elements like shown below (but not used in my ASM11 based example).
RAM equ $0
ROM equ $C000
Vreset equ $FFFE
;*******************************************************************************
#ROM
;*******************************************************************************
org ROM
ARRAY dw 4,144,447,-14,-555,-1147
;QUANTITY equ *-ARRAY/2
;*******************************************************************************
#RAM
;*******************************************************************************
org RAM
absolute rmb ::ARRAY
zeros rmb 1
positives rmb 1
negatives rmb 1
;*******************************************************************************
#ROM
;*******************************************************************************
Start ldx #ARRAY ;X -> source
ldy #absolute ;Y -> destination
;-------------------------------------- ;initialize all counters to zero
clr zeros
clr positives
clr negatives
;--------------------------------------
Loop ldd ,x ;D = word to test
beq CountZero ;go count zero
bpl CountPositive ;go count positive number
;--------------------------------------
inc negatives ;count negative number
; negd ;make it positive (abs)
coma
comb
addd #1
bra Cont
;--------------------------------------
CountZero inc zeros
bra Cont
;--------------------------------------
CountPositive inc positives
; bra Cont
;--------------------------------------
Cont std ,y ;save absolute value
ldab #2 ;B = word size
abx ;X -> next word
aby ;Y -> next word
cpx #ARRAY+::ARRAY ;check for end of array
blo Loop ;repeat for all elements
bra *
org Vreset
dw Start
顺便说一句，您的C代码不正确.我想你打算写这样的东西:
BTW, your C code is incorrect. I think you meant to write something like this:
#include <stdio.h>
#define SIZE 16
int absolute(int array[], int ray[], int N)
{
for (int i=0; i<N; i++)
ray[i] = array[i] * (array[i]<0?-1:1);
}
int main()
{
int array[SIZE] = {0,1,2,3,-4,5,6,7,-8,9,-10,11,12,13,14,20};
int ray[SIZE];
absolute(array,ray,SIZE);
for (int i = 0; i < SIZE; i++ )
printf("The absolute value of %3i is %3i\n", array[i],ray[i]);
return 0;
}
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