ES6类文字中的IIFE [英] IIFE in ES6 class literal

问题描述

在ES5中，我们所有人都可以这样做:

In ES5 we all could do like this:

myClass.prototype.myMethod = (function () {return function() {}})();

我可以用ES6类文字做同样的技巧吗?

Am I able to do the same trick with ES6 class literals?

推荐答案

否，至少尚未. ES6类仅支持声明方法，因此任何非直接方法的东西(包括间接评估方法的东西，例如IIFE)都必须与原型一起声明.

No, not yet at least. ES6 classes only have support for declaring methods, so anything that's not directly a method (this includes things that indirectly evaluate to a method, such as IIFE) must still be declared with the prototype.

但是，ES6类的工作原理实际上与ES5构造函数相同，只是语法更加简洁，因此您仍然可以这样做:

However, ES6 classes really work the same as ES5 constructor functions do, only with a bit cleaner syntax, so you can still do this:

class MyClass {
  constructor() {
    /* initialize */
  }

  regularMethod() {
    /* some stuff */
  }
}

MyClass.prototype.myMethod = (function() { return function() })()

这等效于此:

function MyClass() {
  /* initialize */
}

MyClass.prototype.regularMethod = function() {
  /* some stuff */
}

MyClass.prototype.myMethod = (function() { return function() })()

这篇关于ES6类文字中的IIFE的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！