如何在gulp-replace中使用捕获组? [英] How to use a Capture Group with gulp-replace?

问题描述

口香糖替换0.5.4

gulp-replace 0.5.4

当前:

<link rel="stylesheet" href="assets/styles/app-3c224ff086.css">

目标:

<link rel="stylesheet" href="assets/styles/app-3c224ff086.css" media="screen">

结果:

<link rel="stylesheet" href="$1" media="screen">

初始测试为: https://regex101.com/r/miM7TN/1 .我可能已将测试链接到$ 0捕获组，但是在我的项目中，我使用的是捕获组1.

Initial test was: https://regex101.com/r/miM7TN/1 . I might have linked the test with a capture group of $0, but in my project I am using capture group 1.

在我的gulp任务中添加了以下内容:

In my gulp task the following is added:

var regex = /\"assets\/styles\/app-+.*\"/;
var subst = `$1 media="screen"`;
.pipe(replace(regex, subst))

找到我的字符串，包括开始和结束引号.而不是捕获组，我得到的是原汁原味的$ 1.如何获取捕获组的实际值? gulp-replace文档显示替换值'$ 1foo'. SO上类似的问题显示"$ 1"和"$ 1"，我还没有看到与我的情况有所不同的地方.我尝试过反引号，单引号和双引号.

My string, to include start and end quotes, is being found. Instead of a capture group I am getting a literal $1. How do I get the actual value of the capture group? The gulp-replace documentation shows a replace value '$1foo'. Similar questions on SO show '$1' and "$1", and I am not yet seeing the difference to my situation. I've tried back-ticks, single quotes, and double quotes.

推荐答案

$1后向引用引用ID为1的捕获组，即使用模式中的第一个(...)捕获的文本.

The $1 backreference refers to a capturing group with ID 1, the text captured with the first (...) in your pattern.

您必须使用

 var regex = /("assets\/styles\/app-+.*")/;

使$1能够像$&一样工作"(对整个匹配值的反向引用).

for $1 to "work" the same way as $& (backreference to the whole match value).

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