为什么没有2字节浮点数,并且已经存在实现? [英] Why is there no 2-byte float and does an implementation already exist?
问题描述
假设我真的很想获得内存,并且想要一个较小的范围(类似于short
与int
).着色器语言已经为浮点类型提供了一半精度的half
支持(不仅仅是将值在-1和1之间来回转换,即返回如下所示的浮点数:shortComingIn / maxRangeOfShort
). 2字节浮点数已经存在吗?
Assuming I am really pressed for memory and want a smaller range (similar to short
vs int
). Shader languages already support half
for a floating-point type with half the precision (not just convert back and forth for the value to be between -1 and 1, that is, return a float like this: shortComingIn / maxRangeOfShort
). Is there an implementation that already exists for a 2-byte float?
我也想知道为什么没有2字节浮点数(历史原因).
I am also interested to know any (historical?) reasons as to why there is no 2-byte float.
推荐答案
回复:实现:显然有人为C编写了half
,它(当然)可以在C ++中工作:
Re: Implementations: Someone has apparently written half
for C, which would (of course) work in C++: https://storage.googleapis.com/google-code-archive-downloads/v2/code.google.com/cellperformance-snippets/half.c
Re:为什么float
为四个字节:可能是因为在此以下,其精度非常有限.
Re: Why is float
four bytes: Probably because below that, their precision is so limited.
这篇关于为什么没有2字节浮点数,并且已经存在实现?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!