如何解码监听端口162(Snmp Trap)的结果? [英] how to decode the result of listenning to port 162 (Snmp Trap)?

问题描述

我想使用自己的traplistener获取snmp陷阱.实际上，我使用了在Internet上找到的代码，我对其进行了一些修改，现在可以正常工作了.我可以通过端口162进行监听.

I want to get the snmp trap by using my own traplistener. In fact, I used a code found in internet I added some modifications and now it is working. I can listen through the port 162.

#include "stdio.h"
#include "winsock2.h"
#pragma comment(lib, "ws2_32.lib")
#define SNMP_TRAP_PORT 162
#define MAX_MSG 400

static void init(void)
{

  WSADATA wsa;
    int err = WSAStartup(MAKEWORD(2, 2), &wsa);
    if(err < 0)
    {
        puts("WSAStartup failed !");
        exit(EXIT_FAILURE);
    }

}

static void end(void)
{

    WSACleanup();

}

int main(int argc, char *argv[]) {


  int sd, rc, n, cliLen;
  struct sockaddr_in cliAddr, servAddr;
  char msg[MAX_MSG];



  /* socket creation */
  init(); 
  sd= socket(AF_INET, SOCK_DGRAM, 0);
  if(sd<0) {
    printf("can't open socket \n");
    exit(1);
  }

  /* bind local server port */
  servAddr.sin_family = AF_INET;
  servAddr.sin_addr.s_addr = htonl(INADDR_ANY);
  servAddr.sin_port = htons(SNMP_TRAP_PORT);
  rc = bind (sd, (struct sockaddr *) &servAddr,sizeof(servAddr));
  if(rc<0) {
    printf("can't bind port number %d \n", SNMP_TRAP_PORT);
    exit(1);
  }

  printf("waiting for SNMP Traps on UDP port %d\n", SNMP_TRAP_PORT);

  /* server infinite loop */
  while(1) {

    /* init buffer */
    memset(msg,0x0,MAX_MSG);


    /* receive message */
    cliLen = sizeof(cliAddr);
    n = recvfrom(sd, msg, MAX_MSG, 0, (struct sockaddr *) &cliAddr, &cliLen);

    if(n<0) {
      printf("%s: cannot receive data \n",argv[0]);
      continue;
    }
    /*message is encoded with ASN1 and should be decoded*/  
    /* print received message */
    printf("SNMP Trap received from %s : %o\n", inet_ntoa(cliAddr.sin_addr),msg);


  }/* end of server infinite loop */
end();
return 0;

}

当我收到陷阱时，该代码现在可以正常工作了，我收到一个号码.通常，我应该使用ASN1(十六进制或bin)捕获陷阱，但我得到的只是: Traplistner结果. 我想知道12175440是什么意思. 谢谢

The code works fine now when I get traps I receive a number. Normally, I should get the trap in ASN1 (hex or bin) but I get just this: Traplistner result. I was wondering what does the 12175440 means. Thx

推荐答案

简短答案；它是用八进制写的msg的内存地址.

Short answer; it is the memory address of msg written in octal.

如果您是在具有32位int和64位指针的小端计算机上运行此代码，则很可能是msg地址的低32位.

If you are running this code on a little-endian machine with 32-bit int and 64-bit pointers, it is most likely the lower 32 bits of the address of msg.

这是由于两个薄片的组合造成的:

This is due to a combination of two thins:

1. printf格式说明符%o将参数数据中的下一个字节解释为整数，并将其打印为八进制.

1. The printf format specifier %o interprets the next bytes in the argument data as an integer and prints it in octal.

将数组作为参数传递给函数将转换为将指针传递给第一个元素.因此，这些语句是等效的:

Passing an array as an argument to a function is converted into passing a pointer to the first element. So these statements are equivalent:

printf("%p\n", msg);
printf("%p\n", &msg[0]);

要实际打印您收到的数据，请添加以下内容:

To actually print the data you received, add the following:

for (int i = 0; i < n; ++i) {
    printf("%02x ", (unsigned char)msg[i]);
}
printf("\n");

这篇关于如何解码监听端口162(Snmp Trap)的结果?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！