UITableView中具有多个部分的Search Controller [英] Search Controller with multiple section in UITableView

问题描述

我有一个UIViewController，其中有一个UITableView，并且在该tableview中，我有多个节，其中包含一些项目，我必须在该tableview中使用itemname搜索.我已经在我的视图控制器中声明了这一点

I have a UIViewController in which I have a UITableView and inside that tableview I have multiple sections which have some item and I have to search with itemname inside that tableview. I have declared this in my view controller

let searchController = UISearchController(searchResultsController: nil)

override func viewDidLoad() {
    super.viewDidLoad()
    searchController.dimsBackgroundDuringPresentation = false
    definesPresentationContext = true
    tableView.tableHeaderView = searchController.searchBar
    searchController.searchBar.barTintColor = UIColor(red: 39.0/255.0, green: 203.0/255.0, blue: 192.0/255.0, alpha: 1.0)
    searchController.searchBar.tintColor = UIColor.white
    searchController.searchBar.placeholder = "Search item"

    var sections = [Category A, Category B, Category C]
    var itemsA = [["Item": "item A","ItemId" : "1"],["Item": "itemB","ItemId" : "2"],["Item": "item C","ItemId" : "3"]]
    var itemsB = [["Item": "item A","ItemId" : "1"],["Item": "itemB","ItemId" : "2"],["Item": "item C","ItemId" : "3"]]
    var itemsC = [["Item": "item A","ItemId" : "1"],["Item": "itemB","ItemId" : "2"],["Item": "item C","ItemId" : "3"]]
 }

func numberOfSections(in tableView: UITableView) -> Int {
    if searchController.isActive {
        return 1
    }
    return self.sections.count
}

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

    if searchController.isActive {
        return filteredShops.count
    }
switch (section) {
    case 0: 
       return itemsA.count
    case 1: 
       return itemsB.count
    default: 
       return itemsC.count
    }
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "StoreCell") as! UITableViewCell

    if searchController.isActive {
         let filter = filteredShops[indexPath.row]
         cell.storeName.text = filter["itemName"]
    }
    switch (indexPath.section) {
        case 0: 
            //Access itemsA[indexPath.row]
        case 1: 
            //Access itemsB[indexPath.row]
        default: 
           //Access itemsC[indexPath.row]
    }
 return cell
}

func filteredshops(_ searchText: String, scope: String = "All") {
    let filteredShopsA = storeLists.filter({ item in
        if let name = item["itemName"], let query = searchController.searchBar.text {
            return name.range(of: query, options: [.caseInsensitive, .diacriticInsensitive]) != nil
        }
        return false
    })
    let filteredShopsB = medicalLists.filter({ item in
        if let name = item["itemName"], let query = searchController.searchBar.text {
            return name.range(of: query, options: [.caseInsensitive, .diacriticInsensitive]) != nil
        }
        return false
    })
    let filteredShopsC = restaurantsLists.filter({ item in
        if let name = item["itemName"], let query = searchController.searchBar.text {
            return name.range(of: query, options: [.caseInsensitive, .diacriticInsensitive]) != nil
        }
        return false
    })
    filteredShops = filteredShopsA + filteredShopsB + filteredShopsC
    print(filteredShops)
    tableView.reloadData()
}

并且我具有SearchResultUpdate的扩展名

And I have an extension of SearchResultUpdate

extension NearByShopVC: UISearchResultsUpdating {
    func updateSearchResults(for searchController: UISearchController) {
        filteredshops(searchController.searchBar.text!)
    }
}

我已经提到了这个问题，但是没有找到任何解决方法如何在'updateSearchResultsForSearchController'中过滤字典数组以使用Swift搜索UITableView

I had refer this question but not found any solution How can I filter an array of dictionaries in 'updateSearchResultsForSearchController' to search a UITableView with Swift

我尝试了上述问题中的相应部分，但也未显示正确的结果.谢谢！！

I tried without the section in the above said question then also not showing proper results. Thank you!!

推荐答案

您可以使用的一种方法是过滤单个部分的内容，因此首先要像这样更改filteredshops.

One way for you to is when you filter work with single section, so first change your filteredshops like this way.

func filteredshops(_ searchText: String, scope: String = "All") {
    let filteredShopsA = itemA.filter({ item in
        if let name = item["itemName"], let query = searchController.searchBar.text {
            return name.range(of: query, options: [.caseInsensitive, .diacriticInsensitive]) != nil
        }
        return false
    })
    let filteredShopsB = itemB.filter({ item in
        if let name = item["itemName"], let query = searchController.searchBar.text {
            return name.range(of: query, options: [.caseInsensitive, .diacriticInsensitive]) != nil
        }
        return false
    })
    let filteredShopsC = itemC.filter({ item in
        if let name = item["itemName"], let query = searchController.searchBar.text {
            return name.range(of: query, options: [.caseInsensitive, .diacriticInsensitive]) != nil
        }
        return false
    })
    filteredShops = filteredShopsA + filteredShopsB + filteredShopsC 
    tableView.reloadData()
}

现在使用tableView方法可以像这样进行更改.

Now with tableView method make change like this way.

func numberOfSections(in tableView: UITableView) -> Int {
    if searchController.isActive {
        return 1
    }
    return self.sections.count
}

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    if searchController.isActive {
        return filteredShops.count
    }   
    switch (section) {
    case 0: 
       return itemsA.count
    case 1: 
       return itemsB.count
    default: 
       return itemsC.count
    }
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "StoreCell") as! UITableViewCell
    if searchController.isActive {
        //Access filteredShops array 
    }  
    else {  
        switch (indexPath.section) {
        case 0: 
            //Access itemsA[indexPath.row]
        case 1: 
            //Access itemsB[indexPath.row]
        default: 
            //Access itemsC[indexPath.row]
        }
    }
    return cell
}

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