取消混淆API获取帐户信息 [英] Unfuddle API get accounts info

查看:103
本文介绍了取消混淆API获取帐户信息的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用ActiveResource从Unfuddle API获取帐户信息

I'm trying to get the account info from Unfuddle API using ActiveResource

网址为http://mydomain.unfuddle.com/api/v1/account

这是我的ActiveResource类

this is my ActiveResource class

class Account < ActiveResource::Base
  self.collection_name = "account"
  self.site = "https://mydomain.unfuddle.com/api/v1"
  self.user = "me"
  self.password = "pass"
end

如果我尝试通过Account.all获取我的帐户信息,我会得到一个空数组,但如果尝试这样做

if I try getting my account info with Account.all I'll get an empty array but if I try this

require 'net/https'

UNFUDDLE_SETTINGS = {
  :subdomain  => 'mydomain',
  :username   => 'me',
  :password   => 'pass',
  :ssl        => true
}

http = Net::HTTP.new("#{UNFUDDLE_SETTINGS[:subdomain]}.unfuddle.com",UNFUDDLE_SETTINGS[:ssl] ? 443 : 80)

if UNFUDDLE_SETTINGS[:ssl]
  http.use_ssl = true
  http.verify_mode = OpenSSL::SSL::VERIFY_NONE
end

begin
  request = Net::HTTP::Get.new('/api/v1/account')
  request.basic_auth UNFUDDLE_SETTINGS[:username], UNFUDDLE_SETTINGS[:password]

  response = http.request(request)
  if response.code == "200"
    puts response.body
  else
    puts "HTTP Status Code: #{response.code}."
  end
rescue => e
  puts e.message
end

我得到了我的帐户信息,对为什么ActiveResource方法不起作用有任何想法吗?

I get my account information , any ideas why the ActiveResource approach isn't working ?

**更新

我忘记指定我有此问题 https://github.com/rails/rails/issues/2318 ,然后使用 erikkallens hack.

I forgot to specify that I had this issue https://github.com/rails/rails/issues/2318 and I use erikkallens hack .

推荐答案

似乎是这个问题 https://github.com/rails/rails/issues/2318 ,我尝试了 vaskas 解决方案,但默认情况下它不起作用,我不得不对其进行修改.

It seems to be this issue https://github.com/rails/rails/issues/2318 , I tried vaskas solution but it didn't work by default I had to modify it.

class Account < ActiveResource::Base
  self.collection_name = "account"
  self.site = "https://mydomain.unfuddle.com/api/v1"
  self.user = "me"
  self.password = "pass"
  self.format = AccountXMLFormatter.new
end

class AccountXMLFormatter
  include ActiveResource::Formats::XmlFormat
  def decode(xml)
    [account: ActiveResource::Formats::XmlFormat.decode(xml)]
  end
end

这篇关于取消混淆API获取帐户信息的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆