如何在Java中将日期字符串EEE MMM dd解析为yyyy-MM-dd [英] How to parse date string EEE MMM dd to yyyy-MM-dd in java

问题描述

我在这种模式下使用日期 EEEEE MMMMM yyyy HH:mm:ss.SSSZ ，我想用Java将其转换为yyyy-MM-dd格式，我尝试了以下方法但我收到此异常java.text.ParseException: Unparseable date:

I'm having the date in this pattern EEEEE MMMMM yyyy HH:mm:ss.SSSZ, I would like to convert this to yyyy-MM-dd format in java, I tried below approach but I'm getting this exception java.text.ParseException: Unparseable date:

   SimpleDateFormat formatter = new SimpleDateFormat("dd-MMM-yyyy");
    String dateInString = "Sun Oct 01 00:00:00 EDT 2017";

    try {

        Date date = formatter.parse(dateInString);
        System.out.println(date);
        System.out.println(formatter.format(date));

    } catch (ParseException e) {
        e.printStackTrace();
    }

有人可以帮我解决这个问题吗?

Can someone please help me to resolve this?

谢谢.

推荐答案

在Java-8中，您可以将ZonedDateTime与输入日期的模式为EEE MMM dd HH:mm:ss zzz yyyy

From java-8 you can use the ZonedDateTime with pattern of your input date which is EEE MMM dd HH:mm:ss zzz yyyy

String dateInString = "Sun Oct 01 00:00:00 EDT 2017";

ZonedDateTime time = ZonedDateTime.parse(dateInString,DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss zzz yyyy"));
System.out.println(time.toLocalDate());   //2017-10-01

默认情况下，LocalDate在ISO-8601日历系统中没有时区，例如2007-12-03.

By default LocalDate is without a time-zone in the ISO-8601 calendar system, such as 2007-12-03.

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