领域列表过滤器Swift [英] Realm List Filter Swift
问题描述
var numbersDetail = List is type of ContactDetail()
let predicate = NSPredicate(format: ContactDetail.NUMBER + " = %@", formattedNumber!)
let realmContactDetail = numbersDetail.filter(predicate).first
获取错误:
throw RLMException(此方法只能在RLMArray上调用 从RLMRealm检索到的实例");
throw RLMException("This method may only be called on RLMArray instances retrieved from an RLMRealm");
推荐答案
如果您尝试对Realm Swift List
对象执行查询(实际上是幕后的Objective-C RLMArray
对象),则会发生此错误.在其父对象添加到Realm
之前.
This error occurs if you try and perform a query on a Realm Swift List
object (Which are actually Objective-C RLMArray
objects under the hood) before its parent object has been added to a Realm
.
class Person: Object {
dynamic var name = ""
dynamic var picture: NSData? = nil // optionals supported
let dogs = List<Dog>()
}
let dog = Dog()
dog.name = "Rex"
let person = Person()
person.dogs.append(dog)
let rex = person.dogs.filter("name == 'Rex'") // QUERY WILL TRIGGER EXCEPTION AT THIS POINT
let realm = try! Realm()
try! realm.write {
realm.add(person)
}
let rex = person.dogs.filter("name == 'Rex'") // Query will now work as expected
简而言之,在执行该查询之前,需要确保numbersDetail
属于Realm
.您可以通过选中numbersDetail.realm != nil
轻松地对此进行测试.
In a nutshell, you need to make sure that numbersDetail
belongs to a Realm
before you perform that query. You can easily test this by checking numbersDetail.realm != nil
.
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