确定scipy.sparse矩阵的字节大小? [英] Determining the byte size of a scipy.sparse matrix?

问题描述

是否可以确定scipy.sparse矩阵的字节大小?在NumPy中，您可以通过执行以下操作来确定数组的大小:

Is it possible to determine the byte size of a scipy.sparse matrix? In NumPy you can determine the size of an array by doing the following:

import numpy as np

print(np.zeros((100, 100, 100).nbytes)
8000000

推荐答案

稀疏矩阵是由常规numpy数组构成的，因此您可以像对常规数组那样获取其中任何一个的字节数.

A sparse matrix is constructed from regular numpy arrays, so you can get the byte count for any of these just as you would a regular array.

如果只需要数组元素的字节数:

If you just want the number of bytes of the array elements:

>>> from scipy.sparse import csr_matrix
>>> a = csr_matrix(np.arange(12).reshape((4,3)))
>>> a.data.nbytes
88

如果您想要构建稀疏矩阵所需的所有数组的字节数，那么我认为您想要:

If you want the byte counts of all arrays required to build the sparse matrix, then I think you want:

>>> print a.data.nbytes + a.indptr.nbytes + a.indices.nbytes
152

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