Matlab:如何计算单元中存储了多少个唯一的字符串? [英] Matlab: How to calculate how many unique strings are stored in the cell?
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问题描述
给出一个带有字符串值的单元格,我想计算其中存储了多少个不同的值.以下是示例值:
Given a cell with string values I would like to count how many different values are stored in it. The following ae the example values:
A(1, 1) = 'DA4590162D037A78D96557AA886ADF9715B79C75';
A(2, 1) = 'AFAB19476C2CEEEE101FFA45FD207BA8B6185B29';
A(3, 1) = '99C1F96461BC870574D002034F001BA3F96A9AB5';
...
A(8, 1) = '99C1F96461BC870574D002034F001BA3F96A9AB5';
A(9, 1) = '4B7F0F39C1192D12E6C798143981048D01CDDDD3';
...
大约有3M行.有谁知道计算结构中存储多少个唯一值的方法?
There are approximately 3M rows. Does anyone know the way to calculate how many unique values are stored in the structure?
谢谢!
推荐答案
B = UNIQUE(A)
对于数组A
返回与A
中相同的值,但是
没有重复. B
也将被排序. A
可以是
字符串.
B = UNIQUE(A)
for the array A
returns the same values as in A
but
with no repetitions. B
will also be sorted. A
can be a cell array of
strings.
所以
U = unique(A, 'rows'); %because each string is one row
numUnique = length(U)
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