有什么好的方法可以简化以下逻辑操作? [英] Any good ways to simplify the following logical operation?

问题描述

我正在执行类似于以下逻辑操作的操作:

I am doing the something similar to the following logical operation:

例如，对(x,y), x and y的测试仅采用0或1的值，因此，有4种不同的选择:(0,0), (0,1), (1,0) and (1,1).我希望如果(0,0)发生，则程序执行function00; (0,1) for function01; (1,0) for function10和(1,1) for function11.

For example, test for (x,y), x and y takes values of 0 or 1 only, hence, there are 4 different choices: (0,0), (0,1), (1,0) and (1,1). I want that if (0,0) happens, then the program execute function00; (0,1) for function01; (1,0) for function10 and (1,1) for function11.

当然，我可以使用if then else编写它，但是我想这样做有点长.

Of course, I can use if then else to write it, but I guess it is a little bit length to do it.

if x==0 && y==0
  'run function00'
  else if x==0 && y==1
    'run function01'
    else if x==1 && y==0
      'run function10'
      else if x==1 && y==1
       'run function11'
      end
    end
  end
end

这里要点是使用它-然后-else使代码不可读.我尝试使用switch在某种意义上使其更具可读性:

The point here is using it-then-else makes the codes to be unreadable. I try to use switch to make it more readable in some sense:

switch (x,y)
   case (0,0)
     'run function00'
   case (0,1)
     'run function01' 
   case (1,0)
     'run function10'
   case (1,1)
     'run function11'
end

但是，当我使用switch时，问题是当将大小写设置为(0,0), (0,1), (1,0) and (1,1)时存在语法错误.我想知道如何解决它，或者我不知道的其他操作可以做同样的事情.有人可以提出一些建议吗?在这里，假设我已经定义了function00.m，function01.m，function10.m和function11.m.

However, when I use switch, the problem is that there is a syntax error when I set the cases to be (0,0), (0,1), (1,0) and (1,1). I wonder how to fix it, or other operations that I do not know can do the same thing. Could anybody give some suggestions on it? Here, assuming I have defined function00.m, function01.m, function10.m and function11.m already.

推荐答案

我建议避免使用eval并改用函数句柄.定义函数句柄的单元格数组

I would suggest avoiding eval and using function handles instead. Define a cell array of function handles

>> fh = cell(2,2); 
>> fh{1,1} = @function00; fh{1,2} = @function01; % And so on for all four elements
>> out = fh{x+1,y+1}(); % Where x y are your binary variables

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