Matlab确定曲线 [英] matlab determine curve
问题描述
有人知道如何从原始图中获得具有矩阵的平均曲线,该矩阵具有对应的x,y点吗?我的意思是,我假装一条中等的单曲线.
Does anyone know how to obtain a mean curve having a matrix with the correspondent x,y points from the original plot? I mean, I pretend a medium single curve.
由于我是matlab的新手,所以任何代码或只是想法对我都会非常有帮助. 非常感谢你!
Any code or just ideas would be very very helpful for me since I am new with matlab. Thank you very much!
推荐答案
好吧,您可以做的一件事就是拟合参数曲线.下面是一个示例,该示例如何针对图8上有噪声的情况执行此操作:
Well, one thing you can do is fit a parametric curve. Here's an example on how to do this for a figure-8 with noise on it:
function findParamFit
clc, clf, hold on
%# some sample data
noise = @(t) 0.25*rand(size(t))-0.125;
x = @(t) cos(t) + noise(t);
y = @(t) sin(2*t) + noise(t);
t = linspace(-100*rand, +100*rand, 1e4);
%# initial data
plot(x(t), y(t), 'b.')
%# find fits
options = optimset(...
'tolfun', 1e-12,...
'tolx', 1e-12);
a = lsqcurvefit(@myFun_x, [1 1], t, x(t), -10,10, options);
b = lsqcurvefit(@myFun_y, [1 2], t, y(t), -10,10, options);
%# fitted curve
xx = myFun_x(a,t);
yy = myFun_y(b,t);
plot(xx, yy, 'r.')
end
function F = myFun_x(a, tt)
F = a(1)*cos(a(2)*tt);
end
function F = myFun_y(b, tt)
F = b(1)*sin(b(2)*tt);
end
请注意,这是拟合参数曲线的一种特别糟糕的方法,如此处所示,该解决方案对lsqcurvefit
的初始值的质量非常敏感.尽管如此,拟合参数曲线仍是可行的方法.
Note that this is a particularly bad way to fit parametric curves, as is apparent here by the extreme sensitivity of the solution to the quality of the initial values to lsqcurvefit
. Nevertheless, fitting a parametric curve will be the way to go.
有您的Google查询:)
There's your google query :)
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