MySQL限制与in语句 [英] Mysql limit with in statement
本文介绍了MySQL限制与in语句的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在写查询
SELECT
`user_bookmarks`.`id` as `user_bookmark_id`,
`bookmark_id`,
`user_bookmarks`.`user_id`,
`bookmark_url`,
`bookmark_website`,
`bookmark_title`,
`bookmark_preview_image`,
`bookmark_popularity`,`category_id`,
`category_name`,
`pdf_txt_flag`,
`youtube_video`,
`content_preview`,
`snapshot_preview_image`,
`mode`
FROM
`user_bookmarks`
left join `bookmarks`
on `user_bookmarks`.`bookmark_id` = `bookmarks`.`id`
left join `categories`
on `user_bookmarks`.`category_id` = `categories`.`id`
WHERE
`category_id` IN(164,170,172)
LIMIT 0, 6
它正在获取前6个书签.但我希望它可以从每个类别中获取6个书签.我们可以在mysql本身中做到这一点吗?
it is fetching first 6 bookmarks. But i want it will fetch 6 bookmarks from each category. Can we do this in mysql itself.
请分开...
谢谢
推荐答案
您可以使用排名查询来为每个类别提供排名,并根据所需的每个类别的记录数对其进行过滤,下面的查询将为您提供来自每个类别的6条记录类别
You can use a rank query to give a rank for each category and filter it with your desired no of records per category below query will give you 6 records from each category
SELECT t.* FROM
(SELECT
`user_bookmarks`.`id` AS `user_bookmark_id`,
`bookmark_id`,
`user_bookmarks`.`user_id`,
`bookmark_url`,
`bookmark_website`,
`bookmark_title`,
`bookmark_preview_image`,
`bookmark_popularity`,
`category_id`,
`category_name`,
`pdf_txt_flag`,
`youtube_video`,
`content_preview`,
`snapshot_preview_image`,
`mode` ,
@r:= CASE WHEN category_id = @g THEN @r+1 ELSE @r:=1 END `rank` ,
@g:=category_id
FROM
`user_bookmarks`
LEFT JOIN `bookmarks`
ON `user_bookmarks`.`bookmark_id` = `bookmarks`.`id`
LEFT JOIN `categories`
ON `user_bookmarks`.`category_id` = `categories`.`id`
JOIN (SELECT @r:=0,@g:=0) t1
WHERE `category_id` IN (164, 170, 172)
ORDER BY category_id
) t
WHERE t.rank <=6
这篇关于MySQL限制与in语句的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文