使用Terraform创建多个EBS卷的快照 [英] Create snapshots of multiple EBS volumes using Terraform

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本文介绍了使用Terraform创建多个EBS卷的快照的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用Terraform基于特定AWS区域中的标签创建某些EBS卷的快照. 我曾尝试根据标签过滤EBS卷.当在filter属性中仅指定一个标记值但对于多个值时,我可以获得清晰的EBS卷id输出,我得到以下错误:

I am trying to create snapshots of certain EBS volumes based on tags in a particular AWS region using Terraform. I have tried filtering EBS volumes based on Tags. I can get a clear output of EBS volume id when only one tag value is specified in the filter attribute but for more than one values, i get the following error:

data.aws_ebs_volume.ebs_volume:data.aws_ebs_volume.ebs_volume:您的 查询返回了多个结果.请尝试更具体的搜索 条件,或将most_recent属性设置为true.

data.aws_ebs_volume.ebs_volume: data.aws_ebs_volume.ebs_volume: Your query returned more than one result. Please try a more specific search criteria, or set most_recent attribute to true.

下面是我的Terraform模板:

Below is my terraform template:

data "aws_ebs_volume" "ebs_volume" {
  filter {
    name   = "tag:Name"
    values = ["EBS1","EBS2","EBS3"]
  }
}
output "ebs_volume_id" {
  value = "${data.aws_ebs_volume.ebs_volume.id}"
}

resource "aws_ebs_snapshot" "ebs_volume" {
  volume_id = "${data.aws_ebs_volume.ebs_volume.id}"
}

有没有一种清晰的方法可以使用terraform中的任何一种循环语句来创建多个EBS卷的快照?

Is there a clear way to create snapshots of multiple EBS volumes using any kind of looping statement in terraform?

推荐答案

您可以使用

You can use the count meta parameter to loop over lists, creating multiple resources or data sources.

在您的情况下,您可以执行以下操作:

In your case you could do something like this:

variable "ebs_volumes" {
  default = [
    "EBS1",
    "EBS2",
    "EBS3",
  ]
}

data "aws_ebs_volume" "ebs_volume" {
  count = "${length(var.ebs_volumes)}"

  filter {
    name   = "tag:Name"
    values = ["${var.ebs_volumes[count.index]}"]
  }
}

output "ebs_volume_ids" {
  value = ["${data.aws_ebs_volume.ebs_volume.*.id}"]
}

resource "aws_ebs_snapshot" "ebs_volume" {
  count     = "${length(var.ebs_volumes)}"
  volume_id = "${data.aws_ebs_volume.ebs_volume.*.id[count.index]}"
}

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